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Veronika [31]
3 years ago
12

A rectangle has a length that is one foot less than twice its width. it the area of the rectangle is 91 square feet then which o

f the following equations could be used to solve for its the width of the rectangle?
Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0

Answer:

Step-by-step explanation:

Well.. First of all, the question says that we are working with a rectangle..

So, the rectangle has a length and width. I'll call them L and w.

Look at this phrase: " length that is one foot less than twice its width"

it means, in a algebraic language: L = 2w - 1

Let's analysis the next phrase: "it the area of the rectangle is 91 square feet"

So, A = 91 ft²

But you have to remember that the rectangle area is a product of L and w.

L x w = 91

They are the following equations that you could be used to solve the system of equations.

Now, you have a system of equations and I suggest you to solve it using the substituition method.

L = 2w - 1

L x w = 91

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\boxed{\underline{\bf \: ANSWER}}

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