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babunello [35]
3 years ago
13

What is the nth term of the quadratic sequence 7 , 14 , 23 , 34 , 47 , 62 , 79?

Mathematics
2 answers:
Harrizon [31]3 years ago
4 0

are you asking for the 9th term or the 10th term?



matrenka [14]3 years ago
4 0

First difference in the sequence is:-

7  9  11  13  15  17

second difference =  2 so nth term contains n2

subtracting  n^2 from the sequence

7    14    23   34    47

1      4     9    16     25    

=  6   10  14  18 22  this is an AP with first term 6 and common diff = 4

so formula is    n^2 + ( 6 + 4(n - 1)

= n^2 + 4n + 2  answer




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Please help and thank you
yulyashka [42]

Answer:

D) 3

Step-by-step explanation:

It is halfway the length of Y and W. 6-3= 3

Note:

Pls notify me if my answer is incorrect for the other users that will see this response. Thank you.

<em>-kiniwih426</em>

5 0
3 years ago
Read 2 more answers
Of all the soft drink consumers in a particular sales region, 30% prefer Brand A and 70% prefer Brand
victus00 [196]

Answer:

Option D -0.67

Step-by-step explanation:

Given : Preference of Brand A =30% ⇒ P(A)=\frac{30}{100}=0.3

Preference of Brand B =70% ⇒ P(B)=\frac{70}{100}=0.7

Prefer Brand A and are Female = 20% ⇒ P(A/F)=\frac{20}{100}=0.2

Prefer Brand B and are Female = 40% ⇒ P(B/F)=\frac{40}{100}=0.4

To find : Selected consumer is female, given that the person prefers Brand A P(F/A)

Solution : Using Bayes' theorem, which state that

P(A/B)=\frac{P(B/A)P(A)}{P(B)}

where, P(A) and P(B) are probabilities of observing A and B.

P(B/A)= is a conditional probability where event B occur and A is true

P(A/B)= also a conditional probability where event A occur and B is true.

Now, applying Bayes' theorem,

P(F/A)=\frac{P(A/F)P(A)}{P(B)P(B/F)+P(A)P(A/F)}

P(F/A)=\frac{(0.2)(0.3)}{(0.7)(0.4)+(0.3)(0.2)}

P(F/A)=\frac{0.6}{0.28+0.6}

P(F/A)=\frac{0.6}{0.88}

P(F/A)=0.68

Therefore, Option D is correct probability that a randomly selected consumer is female, given that the person prefers Brand A -0.67

3 0
3 years ago
Read 2 more answers
Can I get the answers for number 14 plz?
nataly862011 [7]
A.
-1: 
2(2)^{-1}  \\ 2( \frac{1}{2}) \\  \frac{2}{2}  \\ 1
(-1,1)

0:
2(2)^{0} \\ 2(1) \\ 2
(0, 2)

1:
2(2)^{1}  \\ 2(2) \\ 4
(1, 4)

2:
2(2)^{2} \\ 2(4) \\ 8
(2, 8)

3:
2(2) ^{3}  \\ 2(8) \\ 16
(3,16)

b.
To graph the equation, simply go through the points (-2, 0.5), (-1, 1), (0,2), (1,4), (2,8), and (3,16). Make sure you never go below 0 on the x-axis, because there's an asymptote there.

Hope this helps!
8 0
3 years ago
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If you multiply two decimals less than 1,can you predict whether the product will be less or greater than either of the factors?
jek_recluse [69]
You can predict that it will be less then either of the factors. if you take half of half from anything will you ever have more than half of the original. 
-i know its a little confusing its the best i could come up with

4 0
3 years ago
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If f(x) = -(1/x^3) and x takes on successive values from -10 to 0.1 ,
prohojiy [21]
Alright, this one is a little interesting... Let's perform some tests to figure out what is happening:
f(-10) = -(1/(-10)^3) = -(1/-1000) = 1/1000  (positive)
f(-5) = -(1/(-5)^3) = -(1/-125) = 1/125 (positive, bigger than the last one)
f(-1) = -(1/(-1)^3) = -(1/-1) = 1 (positive, bigger than the last one)
f(-0.1) = -(1/(-0.1)^3) = -(1/-0.001) = 1/0.001 = 1000 (positive, bigger than the last one)
f(0) = -(1/0^3) = undefined!
f(0.1) = -(1/(0.1)^3) = -(1/0.001) = -1/0.001 = -1000 (negative)
f(1) = -(1/1^3) = -(1/1) = -1 (negative, but bigger than last one)

It's a little confusing with the undefined part at x = 0. What I can say is this, it is increasing from -10 up to 0, something weird happens at 0 and it resets, and starts increasing from 0 up to 0.1. 

I guess A would be the best answer?

3 0
3 years ago
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