To solve this problem, create two equations with x and y. The pieces of information that we know are that the first child is 3 times older than the second child. Therefore if we assign child #1 the variable of x and child #2 the variable of y, we could get the following equation:
3x = y
Now, we also know that together their ages equal 50 months. Therefore:
x + y = 50 (months)
So, using these two equations you can use either substitution or elimination to find the values of x and y. You would first need to rearrange the first equation to 3x - y = 0 (just moving the y to the other side).
Then, you could add the equations together as followed:
3x - y = 0
x + y = 50
___________
4x = 50
x = 12.5
And then fill that value in to one of the equations to find y.
3x = y
3(12.5) = y
y = 37.5
So, one child is 12.5 months old and the other is 37.5 months old!
I wish i could show u how to work it out but just do it or work it out the same way as the fractional numbers.
Answer:
P = 49°
R = 131°
Q = 114°
S = 66°
Step-by-step explanation:
in a quadrilateral inscribed in a circle, the opposite angles are always supplementary, meaning they add up to 150
we are given opposite angles P and R (S is not given so we can't use Q and S)
P+R = 180
5y+14 + 15y + 26 = 180
20y + 40 = 180
20y = 140
y = 7
so...
P = 5(7) + 14 = 35 + 14 = 49
R = 180-49 (since opposite angles in inscribed quadrilaterals are supplementary) = 131
Q = (7)^2 + 65 = 49 + 65 = 114
S = 180-114 = 66
Answer:
Step-by-step explanation
just plug in 0 for z so it would change to -2<6
