Answer:
c
Step-by-step explanation:
Hey There!
So the first thing we want to do is find out what an outlier is
An outlier are points that are distanced from the cluster of points and in this scatterplot there seems to be an outlier ( the point on the bottom right)
so the answer is c
<em>The1AndOnlyMarkus</em>
Answer:
i)D:
ii)R: 
iii) Y-int:(0,-1)
Step-by-step explanation:
i) The given absolute value function is;
.
The absolute value function is defined for all real values of x.
The domain is all real numbers.
ii) The range is all y-values that will make x defined.
The given function,
.
has vertex at, (-2,-3) and opens upwards.
This implies that, the minimum y-value is -3.
The range is
iii) To find the y-intercept substitute x=0 in to the function.
.
.
.
.
The y-intercept is (0,-1)
See attachment for graph.
Answer:
Hey there!
The answer is 2 1/4, which is 2.25
Let me know if you have any other questions!
It would be A. <span>y = −2x − 4.
Hope this helps!!
</span>
<h3>
Answer: 126</h3>
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Work Shown:
Let x and y be the two numbers.
We're given x = 162 and the variable y is unknown.
We're also given LCM = 1134 and HCF = 18
So,
LCM = (x*y)/HCF
1134 = 162*y/18
1134 = (162/18)y
1134 = 9y
9y = 1134
y = 1134/9
y = 126
The other number is 126
---------------------
Notice that
showing that 18 is the highest common factor (HCF) of the numbers 162 and 126. This partially confirms the answer.
Now let,
- A = multiples of 162
- B = multiples of 126
So,
- A = 162, 324, 486, 648, 810, 972, 1134, 1296, ...
- B = 126, 252, 378, 504, 630, 756, 882, 1008, 1134, 1260, ...
We see that 1134 is in each list of multiples and the smallest such common item. So the lowest common multiple (LCM) of 162 and 126 is 1134. This helps fully confirm the answer.
