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Lubov Fominskaja [6]
3 years ago
15

Which of the sets of elements are not in order of increasing force of attraction on the outermost electron in atoms of that elem

ent?
Ba < Sr < Ca
Al < P < Cl
F < Cl < Br
Mo < Pd < Sn
Chemistry
1 answer:
BabaBlast [244]3 years ago
5 0

Answer:

The set of elements that are not arranged in the order of increasing ionization energy is Mo < Pd < Sn

Explanation:

The force of attraction on the outermost electron of an element can be described by the ionization energy of the element which decreases down a group and increases across a period

1) The given elements Ba, Sr, Ca, are group 2 elements arranged in the order from bottom up, which gives an increasing ionization energy, therefore;

Ba < Sr < Ca is arranged in increasing ionization energy, and therefore, increasing force of attraction of the outermost electron in atoms of the elements

Similarly, Al < P < Cl and Mo < Pd < Sn, are arranged in order of increasing ionization energy

However F < Cl < Br which are arranged from top down of elements in period 17 are arranged in the order of decreasing ionization energy, and therefore, decreasing force of attraction of the outermost electron in atoms of the elements.

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Describe a physical change and a chemical change that an iron nail could undergo.
galina1969 [7]
Physical change

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chemical change

iron nail can rust due to the exposure to the air(oxygen). iron in the nail and oxygen in the air will react together to form iron oxide(rust).
furthermore, the reaction is irreversible.
8 0
3 years ago
1. A part of a neuron is a(n) A. nerve B. cell body C. receptor D. acetylcholine
katovenus [111]
A neuron has 4 basic part the dendrites the cell body
I think the answer is b.the cell body
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3 0
3 years ago
A glass flask of volume 400cm is just filled with mercury at 0 degree ​
3241004551 [841]

<em>A glass flask of volume 400 cm³ is just filled with mercury at 0°C. How much mercury will  overflow when the temperature of the system rises to 80°C.​</em>

<em />

The volume of mercury that overflow is 5.376 cm³

<h3>Further explanation</h3>

Given

volume of glass = 400 cm³

Δt=80 °C - 0 °C = 80

Required

overflow volume

Solution

With an increase in the temperature of the substance, objects can expand. This expansion includes volume expansion.

Can be formulated

\tt V_t=V_o(1+\gamma.\Delta t)\\\\\Delta V=V_o.\gamma.\Delta t

Find volume expansion of glass and mercury

  • Glass(γ = 1.2.10⁻⁵ C⁻¹)

\tt \Delta V=400\times 1.2.10^{-5}.80=0.384~cm^3

  • Mercury(γ=1.8.10⁻⁴ C⁻¹)

\tt \Delta V=400\times 1.8.10^{-4}\times 80=5.76~cm^3

Overflow :

ΔV mercury - ΔV glass : 5.76-0.384 = 5.376 cm³

7 0
3 years ago
3 Cu + SHNO3 — 3 Cu(NO3)2 + 2 NO + 4 H20
LenaWriter [7]

Considering the reaction stoichiometry, the mass of H₂O that is produced when 11.9 moles of HNO₃ react is 107.1 grams.

<h3>Reaction stoichiometry</h3>

The balanced reaction is:

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:  

  • Cu: 3 moles
  • HNO₃: 8 moles
  • Cu(NO₃)₂: 3 moles
  • NO: 2 moles
  • H₂O: 4 moles

The molar mass of the compounds present in the reaction is:

  • Cu: 63.54 g/mole
  • HNO₃: 63 g/mole
  • Cu(NO₃)₂: 187.54 g/mole
  • NO: 30 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of mass of each compound participate in the reaction:  

Cu: 3 moles ×63.54 g/mole= 190.62 grams

HNO₃: 8 moles ×63 g/mole= 504 grams

Cu(NO₃)₂: 3 moles ×187.54 g/mole= 562.62 grams

NO: 2 moles ×30 g/mole= 60 grams

H₂O: 4 moles ×18 g/mole= 72 grams

<h3>Mass of H₂O produced</h3>

It is possible to determine the the amount of mass of H₂O produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 72 grams of H₂O, if 11.9 moles of HNO₃ react how much mass of H₂O will be formed?

mass of H_{2}O=\frac{11.9 moles of HNO_{3} x72 grams of H_{2}O}{8 moles of HNO_{3}}

<u><em>mass of H₂O= 107.1 grams</em></u>

In summary, the mass of H₂O that is produced when 11.9 moles of HNO₃ react is 107.1 grams.

Learn more about reaction stoichiometry:

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brainly.com/question/6061451?referrer=searchResults

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Answer:

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Explanation:

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