Option 2.
1. Simplify 7 + (12 - 9) + 7 × 3(8 - 5)
According to the Order of Operations, contents of parentheses are evaluated first. This gives
... 7 + 3 + 7 × 3 × 3
Then multiplication and division are performed left to right.
... = 7 + 3 + 21 × 3
... = 7 + 3 + 63
Followed by addition and subtraction left to right.
... = 10 + 63
... = 73
A Google search box can be relied upon to do the operations in the correct order.
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2. When the expression is rewritten, a different result is obtained. This is because the operations indicated by the second set of parentheses are altered.
... (7 + 12) - 9 + (7 × 3)8 - 5
... = 19 - 9 + 21 × 8 - 5
... = 19 - 9 + 168 - 5
... = 10 + 168 - 5
... = 178 - 5
... = 173
In the first expression, both +8 and -5 are multiplied by 21. In the rewritten expression, only +8 is multiplied by 21.
Answer:
The co variance of the midterm and final exam scores is 58.76.
Step-by-step explanation:
The formula to compute the sample co variance is:
![Cov(x,y)=\frac{\sum(X-Mean\ of\ X)(Y-Mean\ of\ Y)}{n-1}](https://tex.z-dn.net/?f=Cov%28x%2Cy%29%3D%5Cfrac%7B%5Csum%28X-Mean%5C%20of%5C%20X%29%28Y-Mean%5C%20of%5C%20Y%29%7D%7Bn-1%7D)
The values are computed in the table below.
Compute the co variance as follows:
![Cov(x,y)=\frac{\sum(X-Mean\ of\ X)(Y-Mean\ of\ Y)}{n-1}\\=\frac{646.33}{12-1}\\ =58.76](https://tex.z-dn.net/?f=Cov%28x%2Cy%29%3D%5Cfrac%7B%5Csum%28X-Mean%5C%20of%5C%20X%29%28Y-Mean%5C%20of%5C%20Y%29%7D%7Bn-1%7D%5C%5C%3D%5Cfrac%7B646.33%7D%7B12-1%7D%5C%5C%20%3D58.76)
Thus, the co variance of the midterm and final exam scores is 58.76.
Answer:
O -1+ 3/
Step-by-step explanation:
brainest plz
Answer:
Taking LHS
=1 by cos theta- cos theta
= (1- cos²0)/ cos0
= sin²0/ cos0 ( because 1-cos²0 is also equals to sin²0)
=RHS hence proved