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alekssr [168]
2 years ago
6

Write 165300 in standard form ​

Mathematics
2 answers:
Soloha48 [4]2 years ago
8 0

Answer:

one hundred sixty five thousand and three hundred

Step-by-step explanation:

BARSIC [14]2 years ago
7 0

Hey there!

165300 is in standard form.

This is because it is not in scientific notation, in which it would be 1.653 * 10^4.

Hope it helps and have a great day!

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Name the marked angle in 2 different ways.
Ganezh [65]

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Right angle, and angle IJK

Step-by-step explanation:

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2 years ago
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What is the quadratic equation of the curve of best fit shown below
Kisachek [45]
First off, we know that the y-interecept is 2, so there is going to be a plus two in the final equation. Now with the two answers input the number 8 to see which will output 6.

6 = 1/12(8)^(2) + 2
6 = 1/12(64) + 2
6 = 64/12 + 2
6 = 16/3 + 6/3
6 does not equal 22/3

6 = 1/16(8)^(2) + 2
6 = 1/12(64) + 2
6 = 64/16 + 2
6 = 4 + 2
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This means that y = 1/16 x^2 + 2 is the correct answer. I hope that helps!
4 0
3 years ago
Twenty two dollars an hours plus 2.25%
amid [387]

Answer:

how long are you working? what are you asking for?

what is the percentage for?

Step-by-step explanation:

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3 years ago
Please try to give me the answers
gladu [14]

Answer:

a = 1, b = 2, c = 3

Step-by-step explanation:

a +  \frac{1}{b +  \frac{1}{c} }  =  \frac{10}{7}  \\  \\ a +  \frac{1}{b +  \frac{1}{c} }  = 1 +  \frac{3}{7}  \\  \\ a +  \frac{1}{b +  \frac{1}{c} }  = 1 +   \frac{1}{\frac{7}{3} }  \\  \\ a +  \frac{1}{b +  \frac{1}{c} }  = 1 +   \frac{1}{2 + \frac{1}{3} }  \\  \\ equating \: like \: terms \: on \: both \: sides \\  \\ a = 1 \\  \\ b = 2 \\  \\ c = 3

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2 years ago
Solve the inequality and express in interval notation and graph its solution on a number line
vfiekz [6]

Answer:

x ∈ (-∞, 3) U (6, ∞).

Step-by-step explanation:

x^2> 9x - 18

x^2 - 9x + 18> 0

We use factorization and optain

(x-6)(x-3)> 0

Then, we have two critical points: x=3 and x=6. Now:

(i) for x < 3 we have that x-6 <0 and x-3 <0. Then (x-6)(x-3)  > 0.

(ii) for 3 < x < 6 we have that x -6 <0 and x -3 > 0. Then (x-6)(x-3)  < 0.

(iii) for x > 6 we have that x-6 >0 and x-3 > 0. Then, (x-6)(x-3)  > 0.

conditions (i) and (iii) satisfy the inequatliy, then the solution is x ∈ (-∞, 3) U (6, ∞).

The graph is in the picture below.

7 0
3 years ago
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