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Nana76 [90]
3 years ago
8

The sum of five consecutive integers is 185. What is the mean of these five integers?

Mathematics
1 answer:
DedPeter [7]3 years ago
6 0

35, 36, 37, 38, 39 the mean is 37 the median is also 37

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Amelie solves the following system of equations.
PIT_PIT [208]

The values of x and y that satisfy this system of equations are 10 and 5 respectively

<h3>Simultaneous equation</h3>

Given the system of equations

x + y = 20

3x - 3y = 30

_____________________

x + y = 20

x - y = 10

Add the equations

2x = 20 + 10

2x = 30

x = 30/2

x = 15

Substitute

x -y = 10

15 - y = 10

y = 5

Hence the values of x and y that satisfy this system of equations are 10 and 5 respectively

Learn more on simultaneous equation here: brainly.com/question/16863577

#SPJ1

3 0
2 years ago
An arcade booth at a county fair has a person pick a coin from two possible coins available and then toss it. If the coin chosen
nydimaria [60]

Answer:

<em>b. 0.6024</em>

Step-by-step explanation:

<u>Conditional Probability</u>

Suppose two events A and B are not independent, i.e. they can occur simultaneously. It means there is a space where the intersection of A and B is not empty:

P(A\cap B) \neq 0

If we already know event B has occurred, we can compute the probability that event A has also occurred with the conditional probability formula

\displaystyle P(A|B)=\frac{P(A\cap B)}{P(B)}

Now analyze the situation presented in the question. Let's call F to the fair coin with 50%-50% probability to get heads-tails, and U to the unfair coin with 32%-68% to get heads-tails respectively.

Since the probability to pick either coin is one half each, we have

P(U)=P(F)=50\%=0.5

If we had picked the fair coin, the probability of getting heads is 0.5 also, so

P(F\cap H)=0.5\cdot 0.5=0.25

If we had picked the unfair coin, the probability of getting heads is 0.32, so

P(U\cap H)=0.32\cdot 0.5=0.16

Being A the event of choosing the fair coin, and B the event of getting heads, then

P(B)=P(F\cap H)+P(U\cap H)=0.25+0.16=0.41

P(A\cap B)=P(F\cap H)=0.25

\displaystyle P(A|B)=\frac{0.25}{0.41}=0.61

The closest answer is

b. 0.6024

7 0
2 years ago
Which three expressions are equavalent to the expression 3x-12-2(x+12)​
IgorC [24]
3x-12-2x-24
Simplify and you get x-36
6 0
2 years ago
A jewelry store sells charm bracelets and charms. A bracelet with two charms costs $36.00. A bracelet with four charms costs $50
Slav-nsk [51]

Answer:

36+50

Step-by-step explanation:

4 0
3 years ago
Dylan just started a running plan where he runs 14 miles the first week and then increases the number of miles he runs by 10% ea
Vladimir79 [104]

Answer:

36 miles

Step-by-step explanation:

Given - Dylan just started a running plan where he runs 14 miles the first

            week and then increases the number of miles he runs by 10% each

            week.

To find - If he keeps up this plan for 11 weeks, how many total miles would  

              Dylan have run ?

Proof -

1st week = 14 miles

2nd week = 14 + 10% of 14 = 14 + 1.4 = 15.4

3rd week = 15.4 + 10% of 15.4 = 15.4 + 1.54 = 16.94

4th week = 16.94 + 10% of 16.94 = 16.94 + 1.694 = 18.634

5th week = 18.634 + 10% of 18.634 = 18.634 + 1.8634 = 20.4974

6th week = 20.4974 + 10% of 20.4974 = 20.4974 + 2.04974 = 22.54714

7th week = 22.54714 + 10% of 22.54714 = 22.54714 + 2.254714 = 24.801857

8th week = 24.801857  + 10% of 24.801857  = 24.801857  + 2.4801857  = 27.2820427

9th week = 27.2820427  + 10% of 27.2820427  = 27.2820427+ 2.72820427  = 30.01024697

10th week = 30.01024697  + 10% of 30.01024697  = 30.01024697 + 3.001024697  = 33.01127167

11th week = 33.01127167  + 10% of 33.01127167  = 33.01127167 + 3.301127167  = 36.31239884 ≈ 36

∴ we get

Total miles Dylan would run = 36 miles.  

8 0
2 years ago
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