I got 18. i did this by using the SOH CAH TOA method. In this case you have the the angle and the hypotenuse, and you’re looking for the adjacent side, therefore you need to use CAH
Answer and Step-by-step explanation:
C(x) be the statement "x has a cat"
D(x) be the statement "x has a dog"
F(x) be the statement "x has a ferret".
Universe = x = all students in your class.
a) A student in your class has a cat, a dog and a ferret
= ∃x(C(x) ∧ D(x) ∧ F(x))
b) All students in your class have a cat, a dog, or a ferret = ∀x(C(x) ∨ D(x) ∨ F(x))
c) Some students in your class has a cat and a ferret but not a dog = ∃x (C(x) ∧ F(x) ∧ ¬D(x))
d) No student in this class has a cat, a dog and a ferret ¬∃x (C(x) ∧ D(x) ∧ F(x))
e) For each of the three animals, cats, dogs and ferrets, there is as student in your class who has one of the three animals. (∃xC(x)) ∧ (∃xD(x)) ∧ (∃xF(x))
The perimeter of the garden is given
P = 45.45 + 45.45 + 14.63 + 14.63 = 120.16 feet
One picket fence slat is 2 feet wide, so the number of fence Curt should buy is
120.16÷2 = 60.08 rounded to 61 fences
Answer:
Step-by-step explanation:
*There is an acute isosceles (don't know if I am spelling any of these correct)
*Right Scalene
*right isosceles
*equilateral
Those are some of the ones that I found
<span>the sum of the values = 39 </span>× 7 = 273
