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Marat540 [252]
3 years ago
12

Please help i need it !!!

Mathematics
1 answer:
Sedbober [7]3 years ago
3 0

Answer:

x=7

Step-by-step explanation:

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In ΔBCA, CB = 11 cm, CG = 6 cm, AH = 9 cm. Find the perimeter of ΔBCA. Triangle BCA with inscribed circle D. Segments BF and BH,
romanna [79]

Answer:

The perimeter of Δ ABC is 40 cm ⇒ 2nd answer

Step-by-step explanation:

* Lets explain how to solve the problem

- Circle D is inscribed in triangle ABC

- The circle touches the side AB at H , side BC at F , side CA at G

- BF and BH are tangents to circle D from point B

∴ BF = BH ⇒ tangents drawn from a point outside the circle

- CF and CG are tangents to circle D from point C

∴ CF = CG ⇒ tangents drawn from a point outside the circle

- AG and AH are tangents to circle D from point A

∴ AG = AH ⇒ tangents drawn from a point outside the circle

∵ CG = 6 cm ⇒ given

∴ CF = 6 cm

∵ CB = 11 cm ⇒ given

∵ CB = CF + FB

∴ 11 = 6 + FB ⇒ subtract 6 from both sides

∴ FB = 5 cm

∵ FB = BH

∴ BH = 5 cm

∵ AH = 9 cm ⇒ given

∵ AH = AG

∴ AG = 9 cm

∵ AB = AH + HB

∴ AB = 9 + 5 = 14 cm

∵ AC = AG + GC

∴ AC = 9 + 6 = 15 cm

∵ BC = 11 cm ⇒ given

∵ The perimeter of Δ ABC = AB + BC + CA

∴ The perimeter of Δ ABC = 14 + 11 + 15 = 40 cm

* The perimeter of Δ ABC is 40 cm

3 0
3 years ago
|18| what is the absolute value?
Tju [1.3M]
The answer is 18, the answer is always just the number in the brackets( hope this helps)
7 0
3 years ago
Please help with these questions (no links)
seraphim [82]
If the cakes are circles,
3.14(4)2= 50.24
3.14(5)2= 78.5
78.5-50.24= 28.26

#1 is 28.26
3 0
2 years ago
What is the solution to the inequality l2n+5l > 1
posledela
|2n+5| \ \textgreater \  1\\
2n+5\ \textgreater \ 1 \vee 2n+5\ \textless \ -1\\
2n\ \textgreater \ -4 \vee 2n\ \textless \ -6\\
n\ \textgreater \ -2 \vee n\ \textless \ -3\\
n\in(-\infty,-3)\cup(-2,\infty)
7 0
3 years ago
Read 2 more answers
Which equation does not represent a direct variation?
tatuchka [14]
Okay I think there has been a transcription issue here because it appears to me there are two answers. However I can spot where some brackets might be missing, bear with me on that.

A direct variation, a phrase I haven't heard before, sounds a lot like a direct proportion, something I am familiar with. A direct proportion satisfies two criteria:

The gradient of the function is constant s the independent variable (x) varies

The graph passes through the origin. That is to say when x = 0, y = 0.

Looking at these graphs, two can immediately be ruled out. Clearly A and D pass through the origin, and the gradient is constant because they are linear functions, so they are direct variations.

This leaves B and C. The graph of 1/x does not have a constant gradient, so any stretch of this graph (to y = k/x for some constant k) will similarly not be direct variation. Indeed there is a special name for this function, inverse proportion/variation. It appears both B and C are inverse proportion, however if I interpret B as y = (2/5)x instead, it is actually linear.

This leaves C as the odd one out.

I hope this helps you :)
4 0
3 years ago
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