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1 year ago

How would you create a system of linear equations to solve using substitution for this problem?

Mathematics

1 answer:

tino4ka555 [31]1 year ago

5 0

we have

x ----> number of hats the sold

y ----> number of scarves they sold

12x+15y=690 ------> equation A

y=x+10 -----> equation B

Solve the system of equations

Using substitution Method

substitute equation B in equation A

12x+15(x+10)=690

solve for x

12x+15x+150=690

27x=690-150

27x=540

x=20

Find out the value of y

y=x+10

y=20+10

y=30

therefore

The answer is

<h2>20 hats and 30 scarves</h2>

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The US Agency for Healthcare Research and Quality (www.ahrq.gov) reported that in 2010 the mean cost of a stay in a hospital for

zysi [14]

Answer:

We conclude that the population mean cost for a hospital stay for American women aged 18-44 has increased since 2010.

Step-by-step explanation:

We are given that the US Agency for Healthcare Research and Quality reported that in 2010 the mean cost of a stay in a hospital for American women aged 18-44 was $15,200.

A random sample of 400 hospital stays for American women aged 18-44 showed a mean cost of $16,000, with a standard deviation of $5000.

Let $\mu$ = population mean cost for a hospital stay for American women aged 18-44.

SO, Null Hypothesis, $H_0$ : $\mu$ $\leq$ $15,200 {means that the population mean cost for a hospital stay for American women aged 18-44 has reduced or remains same since 2010}

Alternate Hypothesis, $H_A$ : $\mu$ > $15,200 {means that the population mean cost for a hospital stay for American women aged 18-44 has increased since 2010}

The test statistics that will be used here is One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean cost of a stay in a hospital for American women aged 18-44 = $16,000

s = sample standard deviation = $5,000

n = sample of hospital stays = 400

So, test statistics = $\frac{16,000-15,200}{\frac{5,000}{\sqrt{400} } }$ ~ $t_3_9_9$

= 3.20

Now at 5% significance level, the t table gives critical value of 1.645 at 399 degree of freedom for right-tailed test. Since our test statistics is more than the critical value of t as 1.645 < 3.20, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the population mean cost for a hospital stay for American women aged 18-44 has increased since 2010.

8 0

3 years ago

PLATO!! Please help!

KIM [24]

Answer:

B. The sample size is too small to represent the population

Step-by-step explanation:

Logically speaking, this is correct because out of an ENTIRE day of customers entering a craft shop, more than 5 people enter the store. Due to this, Cara should've surveyed a larger number of customers.