Ok so area=pir^2
2 circles with same area=2pir^2
circle with 2 times radius=pi(2r)^2=pi4r^2=4pir^2
is 2 circles with same area equal to circle with 2 times radius?
is 2pir^2=4pir^2?
is 2=4?
no
therfor the answer is no
it is because the radius is squaered so the doubled gets doubled makng it quadrupuled when the first one only gets doubled
Answer:
35°
Step-by-step explanation:
The central arc is equal to the arc that subtends it, then
arc AC = 75° and
BC = AC - AB = 75° - 40° = 35°
Answer:
*1 month later*
Step-by-step explanation:
Answer:

Step-by-step explanation:
In essence, one needs to work their way backwards to solve this problem. Use the information to construct the function.
The function has verticle asymptotes at (x = 4) and (x = 5). This means that the denominator must have (x - 4) and (x - 5) in it. This is because a verticle asymptote indicates that the function cannot have a value at these points, the function jumps at these points. This is because the denominator of a fraction cannot be (0), the values (x - 4) and (x - 5) ensure this. Since if (x) equals (4) or (5) in this situation, the denominator would be (0) because of the zero product property (this states that any number times zero equals zero). So far we have assembled the function as the following:

The function has x-intercepts at (6, 0), and (0, 10). This means that the numerator must equal (0) when (x) is (6) or (10). Using similar logic that was applied to find the denominator, one can conclude that the numerator must be (
). Now one has this much of the function assembled

Finally one has to include the y-intercept of (0, 120). Currently, the y-intercept is (60). This is found by multiplying the constants together. (6 * 10) equals (60). One has to multiply this by (2) to get (120). Therefore, one must multiply the numerator by (2) in order to make the y-intercept (120). Thus the final function is the following:
