Hello there!
(-1)^3 * (-1)^2
Use the distributive property
= (-1)(-1)(-1)* (-1)(-1)
= (-1)^5
= -1
I hope this helps!
There are 30 days in the month of June. Out of the 30 days, Ava saw birds on 18.
P(bird)=18/30
We can simplify the fraction by dividing both sides by 2.
P(bird)=18/30=9/15
9/15=0.6=60%
Theres a 9/15 or 60% chance that she will see a bird on July 1st.
Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:
1. ABC against DEF
2. ABD against CEF
3. ABE against CDF
4. ABF against CDE
5. ACD against BFE
6. ACE against BDF
7. ACF against BDE
8. ADE against BCF
9. ADF against BCE
10. AEF against BCD
I believe there are 12 combinations... I just can't think of the last 2 though.
