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Vlad [161]
2 years ago
8

De

Mathematics
1 answer:
Oksi-84 [34.3K]2 years ago
6 0

Answer:

Tens

PART B: 18

PART C: 24

Step-by-step explanation:im pretty sure

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What’s 0.85 in simplest form
jek_recluse [69]

Answer:

17/20

Step-by-step explanation:

To find the simplest form of 0.85 you need to turn it into a fraction.

To turn it into a fraction you put 85 over 100 since 0.85 is in the hundredths place.

85/100 can be simplified to 17/20 because 85/5 is 17 and 100/5 is 20

5 0
2 years ago
In a school the number of girls is more than twice the number of boys. If the school has 650 students find the greatest number o
Leya [2.2K]

Answer:

750

Step-by-step explanation:

because if the has 650 students and it is the greatest number

8 0
2 years ago
Read 2 more answers
You are ordering a sandwich for lunch. If the sandwich shop boasts that they have 25 different toppings for their sandwiches, an
Blizzard [7]

Step-by-step explanation:

Number of Combinations

= 25C0 + 25C1 + 25C2 + 25C3 + 25C4 + 25C5

= 1 + 25 + 300 + 2300 + 12650 + 53130

= 68,406.

There are a total of 68,406 combinations.

6 0
3 years ago
Read 2 more answers
The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

4 0
3 years ago
Can someone help me. I need to show the box method also can someone show me.
sveta [45]

there's a 3 on the left of the box it got cut out. you jus multiply 3 by 6000, 200, 50, nd 3,, n then add the numbers tht you get in the boxes and if you see my bad handwriting, no you didnt

4 0
3 years ago
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