Answer:
x = 10
y = 3
Step-by-step explanation:
Given
2x - 6y = 2
x + 6y = 28
Add both equations
2x + x -6y + 6y = 2 + 28
3x = 30
Divide both sides by 3
x = 30/3
x = 10
Substitute 10 for x in either equations to get y
Using equation 2 , we have
x + 6y = 28
10 + 6y = 28
Subtract 10 from both sides
10 - 10 + 6y = 28 - 10
6y = 18
Divide both sides by by 6
y = 18/6
y = 3
Therefore
x = 10
y = 3
<h3>
Answer: x^2 + 6</h3>
Work Shown:
(f o g)(x) = f(g(x))
f(x) = x + 7
f( g(x) ) = g(x) + 7 ... replace every x with g(x)
f( g(x) ) = x^2-1 + 7 .... plug in g(x) = x^2-1
f( g(x) ) = x^2 + 6
(f o g)(x) = x^2 + 6
For trapezoid, the area = (upper base + lower base) * height / 2
So area = (12 + (2*2 + 12) ) *13 / 2 = 182
Answer:
the answer is c
Step-by-step explanation:
the answer is c
The interquartile range<span> (</span>IQR<span>) is a measure of variability, based on dividing a </span>data set<span>into quartiles. Quartiles divide a rank-ordered </span>data set<span> into four equal parts. The values that divide each part are called the first, second, and third quartiles; and they are denoted by Q1, Q2, and Q3, respectively.</span>
