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Tems11 [23]
3 years ago
8

Find the coordinates of the midpoint

Mathematics
1 answer:
Bond [772]3 years ago
3 0

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ P(\stackrel{x_1}{-8}~,~\stackrel{y_1}{16})\qquad Q(\stackrel{x_2}{6}~,~\stackrel{y_2}{-8}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{6-8}{2}~~,~~\cfrac{-8+16}{2} \right)\implies \left( \cfrac{-2}{2}~,~\cfrac{8}{2} \right)\implies (-1~,~4)

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A trumpet has a length of 140cm. The first valve lowers the root note by two semitones (f1/f0 = 2-2/12) and the second valve low
Alexxandr [17]

Answer:

a.  17.145cm

b. 8.325cm

c. 0.846

d. 2.896

Step-by-step explanation:

It is known that frequency is inversely proportional to length.

Case 1: The player presses only the first valve.

f₁/fo = 2^{-2/12} = lo/l₁

given that lo= 140cm.

l₁ = 2^{2/12}lo = 157.145

change in length:

l₁ - lo = 157.145 - 140 = 17.145cm

Case 2: The player presses only the second valve.

f₂/fo = 2^{-1/12} = lo/l₂

l₂ = 2^{1/12}lo = 148.325cm

l₂  - lo= 148.325-140 = 8.325cm

Case 3: The player presses both the first and second valve.

Change in length is the sum of change in length when they are individually pressed.

l₃ - lo = 17.145+8.325 = 25.47cm

l₃ = 25.47cm+lo = 165.47cm

f₃/fo  = 2^{-n/12} = lo/l₃

f₃/fo = 2^{-n/12} = 140/{165.47 = 0.846

2^{-n/12} = 0.846\Rightarrow n/12 = -log(0.846)/log(2) = 0.2413

n = 0.2413*12 = 2.896

5 0
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Divide -20.40 and -4
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3 years ago
4 martians, 3 plutonians and 5 jupiterians are to be seated in a row at an interplanetary conference. How many seating arrangeme
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we are given

martians =4

plutonians =3

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total number of seating arrangement is 12!

so, we get

possible seating arrangements are

=\frac{12!}{4!3!5!}

=27720.............Answer

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n = 8×3
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