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2 years ago

Divide. Write your answer in simplest form. 1/9÷5/4=

Mathematics

2 answers:

irina [24]2 years ago

3 0

Answer:

4/45

Step-by-step explanation:

when dividing fractions, you multiply the first fraction by the second fraction's reciprocal :

1/9 divided by 5/4

1/9 multiplied by 4/5

essentially, you switch the signs from division to multiplication, and reverse the second fraction.

1/9 multiplied by 4/5

1/9*4/5 = 4/45

4vir4ik [10]2 years ago

3 0

Answer:

4/45

Step-by-step explanation:

1/9 divided by 5/4

Multiply 4 and 1

Then multiply 9 and 5

Final Answer: 4/45

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2 years ago

A random variable X follows the uniform distribution with a lower limit of 670 and an upper limit of 750.a. Calculate the mean a

DENIUS [597]

You can compute both the mean and second moment directly using the density function; in this case, it's

$f_X(x)=\begin{cases}\frac1{750-670}=\frac1{80}&\text{for }670\le x\le750\\0&\text{otherwise}\end{cases}$

Then the mean (first moment) is

$E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x\,\mathrm dx=710$

and the second moment is

$E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x^2\,\mathrm dx=\frac{1,513,900}3$

The second moment is useful in finding the variance, which is given by

$V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2=\dfrac{1,513,900}3-710^2=\dfrac{1600}3$

You get the standard deviation by taking the square root of the variance, and so

$\sqrt{V[X]}=\sqrt{\dfrac{1600}3}\approx23.09$

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2 years ago