The slope is given as m = 7m=7 and the yy-intercept as b = - \,4b=−4. Substituting into the slope-intercept formula y = mx + by=mx+b, we have
since m=7 and b=-4, we can substitute that into the slope-intercept form of a line to get y=mx+b → y=7x-4
The slope is positive thus the line is increasing or rising from left to right, but passing through the yy-axis at point \left( {0, - \,4} \right)(0,−4).
The answer is C. The numerator 7x+14 can be factored as 7(x+2). The denominator 2x^2+2x-6 can be factored as (x+2)(2x-3). The greatest common divisor of 7(x+2) and (x+2)(2x-3) is obviously x+2, which is contained in both of the two expressions.