1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mestny [16]
3 years ago
14

Using Properties to Simplify Expressions

Mathematics
1 answer:
Fantom [35]3 years ago
4 0

Answer:

1) 2x-3 = x -3 + x

2) 2x - 6 = -6 + 2x

3) \frac{3}{5}-\frac{13}{5}=-6.9+4.9

4) 3x+0 = 3x

5)  \frac{5}{3}-x+\frac{1}{3}=-\frac{3}{2}x+2+\frac{1}{2}x

Step-by-step explanation:

We need to match each expression on the left with an equivalent expression on the right

The expressions are equivalent if the have the same results.

1) 2x - 3

Looking at the options the best match is:

x -3 + x

When solve we get:

2x-3

So, 2x-3 = x -3 + x

2) 2x - 6

Looking at the options the best match is:

-6 + 2x

Because according to commutative property: a+b = b+a

So, 2x - 6 = -6 + 2x

3) \frac{3}{5}-\frac{13}{5}

First simplifying the given expression:

\frac{3}{5}-\frac{13}{5}\\=\frac{3-13}{5}\\=\frac{-10}{5}\\=-2

Looking at the options, -6.9+4.9 = -2

So, \frac{3}{5}-\frac{13}{5}=-6.9+4.9

4) 3x + 0

Looking at the options the best match is:

3x

Because, adding 0 in 3x will result in 3x

So, 3x+0 = 3x

5) \frac{5}{3}-x+\frac{1}{3}

First simplifying:

\frac{5}{3}-x+\frac{1}{3}\\=\frac{5-3x+1}{3}\\=\frac{6-3x}{3}\\=  \frac{3(2-x)}{3}\\=2-x

Now, solving the option: -\frac{3}{2}x+2+\frac{1}{2}x

=\frac{-3x+4+1x}{2}\\=\frac{-2x+4}{2}\\=\frac{2(-x+2)}{2}\\=-x+2\\or\\=2-x

So, \frac{5}{3}-x+\frac{1}{3}=-\frac{3}{2}x+2+\frac{1}{2}x

You might be interested in
2x^(2/3)+5x^(2/3)=686
mrs_skeptik [129]

Answer:

Step-by-step explanation:

4 0
3 years ago
If x/y + y/x = -1 , find the value of x^3 - y^3
marin [14]

Answer:

  0

Step-by-step explanation:

Multiplying the first equation by xy, we have ...

  x^2 +y^2 = -xy

Factoring the expression of interest, we have ...

  x^3 -y^3 = (x -y)(x^2 +xy +y^2)

Substituting for xy using the first expression we found, this is ...

  x^3 -y^3 = (x -y)(x^2 -(x^2 +y^2) +y^2) = (x -y)(0) = 0

The value of x^3 -y^3 is 0.

7 0
3 years ago
Please help me with the answer, ive been stuck on getting both answers for a while now ty
Anettt [7]

Answer:

3x + x - 17 + 13 = 116 \\ 4x = 120 \\ x = 30 \\ g = 73 \\ h = 43

8 0
3 years ago
(56 x10°)-4,000,000 =
AlexFokin [52]
It should be -3999944
3 0
3 years ago
Evan’s family drove to a theme park for vacation. Assume they drove the same speed throughout the trip. The first day, they drov
nadezda [96]
300/6 = 50
250/5 = 50
x/3 = 50
x = 150 miles
4 0
3 years ago
Other questions:
  • The bases on a baseball diamond are 90 feet apart. how far is it from home plate to second base?
    11·2 answers
  • there are red checkers and black checkers,20 checkers in all. There are 8 more red checkers than black checkers. How many red ch
    8·1 answer
  • How could I solve y= 2x^2 + 16x - 66 <br><br> By using quadratic formula?
    12·2 answers
  • Olive walks at a rate of 4 miles per hour she lives 2 miles from the mews station how long wil it talk her to walk home from the
    6·1 answer
  • What is the simplified form of 2 over x squared minus x minus 1 over x ? (2/x^2-x) - (1/x)
    12·1 answer
  • The original price of a pair of jeans is $32 the sales price 15% off the original price what is the amount off the original pric
    5·1 answer
  • I NEED HELP I’ve been stuck on this for a while now and I don’t get it I tried answering this question many times but I can’t ca
    5·1 answer
  • What is the simplified form of -(x-4)<br><br> -x-4<br> -x+4<br> X+4<br> X-4<br><br> Show your work
    6·1 answer
  • If f(x) = 3x - 2 and g(x) = x2 +1, find (*+g)(x).
    9·1 answer
  • Mr. Garza's family is attending the local soccer game. He has 30 to spend on food and drinks . The cost of chips is $2 and the c
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!