You take 187 away from 2431
Answer:
(I) (-5) is a zero of P(x)
(II) 5 is a zero of P(x)
(III) (-5/2) is a zero of P(x)
Step-by-step explanation:
<h3>
(I) P(x) = x + 5</h3>
Here, P(x) = x + 5
To find the zeroes of P(x)
let P(x) = 0
∴ x + 5 = 0
∴ x = (-5)
Thus, (-5) is a zero of P(x)
<h3>(II) P(x) = x - 5</h3>
Here, P(x) = x - 5
To find the zeroes of P(x)
let P(x) = 0
∴ x - 5 = 0
∴ x = 5
Thus, 5 is a zero of P(x)
<h3>(III) P(x) = 2x + 5</h3>
Here, P(x) = 2x + 5
To find the zeroes of P(x)
let P(x) = 0
∴ 2x + 5 = 0
∴ 2x = -5
∴ x = (-5/2)
Thus, (-5/2) is a zero of P(x)
<u>-</u><u>TheUnknownScientist</u>
So if 2 is the first term then if n=1 then n+1=sequence so far but
second term is 9 so if n=2 then the 2nd term=9
you must use trial and error to find
so it is
7n-5 so if n=1 then
7(1)-5=7-5=2
if n=2 then
7(2)-5=14-5=9
sucess
the equation is 7n-5
Answer:
i hope this helps i believe it is 1/3
2 is
Step-by-step explanation:
