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DENIUS [597]
2 years ago
9

Sound travels at a rate of 344 meters in 1 second. How many meters does it travel in 1 minute?

Mathematics
2 answers:
erma4kov [3.2K]2 years ago
8 0

Answer:

2064 meters

Step-by-step explanation:

344*6=2064

Tju [1.3M]2 years ago
7 0

Answer:

20640 meters per minute

Step-by-step explanation:

So, how does 1 go to 60? x 60. Do that to the other side and what do you get? 20640

344 meters                                                          1 second      

x 60                                                                      x 60

20640 meters                                                     60 seconds (1 minute)

Meters                                                                   Seconds

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Answer:

Distance around the circle is perimeter.

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Step-by-step explanation:

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8 0
3 years ago
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A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32
olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

Here the height equation is:

h(t) = -16t^2 + 32t + 6

We can see that the leading coefficient is negative, this means that the arms of the graph will open downwards.

Then, the vertex of the quadratic equation will be the maximum.

Remember that for a general quadratic equation:

a*x^2 + b*x + c = y

the x-value of the vertex is:

x = -b/2a

Then in our case, the vertex is at:

t = -32/(2*-16) = 1

The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

h(t) = -16*t^2 + 32*t + 6

the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

we have that:

df(x)/dx = n*a*x^(n-1)

Then:

v(t) = dh(t)/dt = 2*(-16)*t + 32 + 0

v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

       32*t = 32

            t = 32/32 = 1

So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

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4 0
3 years ago
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monitta

Answer:

<h2><u><em>its B</em></u></h2>

Step-by-step explanation:

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