Question

Find the magnitude of a vector with initial point A(3, 4, 10) and terminal point B(8, 4, –2).

Answer 1

Answer:

B

Step-by-step explanation:

Use the distance formula in 3 dimensions

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2 }$

with (x₁, y₁, z₁ ) = (3, 4, 10) and (x₂, y₂, z₂ ) = (8, 4, - 2)

d = $\sqrt{(8-3)^2+(4-4)^2+(-2-10)^2}$

   = $\sqrt{5^2+0^2+(-12)^2}$

    = $\sqrt{25+144}$

    = $\sqrt{169}$

     = 13 → B