How to solve simliar triangles

Mathematics

1 answer:

8090 [49]3 years ago

7 0

Answer:

there is a formula to solve simlar triangle

Step-by-step explanation:

Ratios and properties-similar figures -In depth.if two object have same shape they are called similar.When two figure are similar,The ratios of the length of their corresponding sides are equal.To determine if the triangle shown are similar,Compare their corresponding sides.

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The length of a phone conversation is normally distributed with a mean of 4 minutes and a standard deviation of .6 minutes. What

Ivanshal [37]

Answer:

0.04746

Step-by-step explanation:

To answer this one needs to find the area under the standard normal curve to the left of 5 minutes when the mean is 4 minutes and the std. dev. is 0.6 minutes. Either use a table of z-scores or a calculator with probability distribution functions.

In this case I will use my old Texas Instruments TI-83 calculator. I select the normalcdf( function and type in the following arguments: :

normalcdf(-100, 5, 4, 0.6). The result is 0.952. This is the area under the curve to the left of x = 5. But we are interested in finding the probability that a conversation lasts longer than 5 minutes. To find this, subtract 0.952 from 1.000: 0.048. This is the area under the curve to the RIGHT of x = 5.

This 0.048 is closest to the first answer choice: 0.04746.

8 0

3 years ago

Suppose a shipment of 120 electronic components contains 3 defective components. to determine whether the shipment should be ac

Likurg_2 [28]

For this problem, the most accurate is to use combinations

Because the order in which it was selected in the components does not matter to us, we use combinations

Then the combinations are $nC_r = \frac{ n! }{r! (n-r)!}$

n represents the amount of things you can choose and choose r from them

You need the probability that the 3 selected components at least one are defective.

That is the same as:

(1 - probability that no component of the selection is defective).

The probability that none of the 3 selected components are defective is:

$P = \frac{_{117}C_3}{_{120}C_3}$

Where $_{117}C_3$ is the number of ways to select 3 non-defective components from 117 non-defective components and $_{120}C_3$ is the number of ways to select 3 components from 120.