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allsm [11]
3 years ago
11

If 45 mL of a 6 M solution is diluted to a final volume of 250 mL, what is concentration of the final solution?

Chemistry
1 answer:
Andrew [12]3 years ago
5 0

Answer:

1.08 M

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 45 mL

Initial concentration (C₁) = 6 M

Final volume (V₂) = 250 mL

Final concentration (C₂) =?

The final concentration of the solution can be obtained by using the dilution formula as illustrated below:

C₁V₁ = C₂V₂

6 × 45 = C₂ × 250

270 = C₂ × 250

Divide both side by 250

C₂ = 270 / 250

C₂ = 1.08 M

Therefore, the final concentration of the solution is 1.08 M.

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\displaystyle n = \frac{m}{M} = \frac{16.3}{24.301} = 0.670644\;\text{mol}.

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\displaystyle n = \frac{m}{M} = \frac{4.33}{15.999} = 0.270642\;\text{mol}.

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What's the mass of 0.541284 moles of MgO?

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Mass of 0.541284 moles of MgO:

m = n \cdot M = 0.541284\times 40.300 = 21.8\;\text{g}.

7 0
3 years ago
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