The given complex Ion is,
[Co(CN)₃]³⁻
In complex compounds the Positive part is named first, followed by name of Negative part. In given case there is no Positive part. So, we will name the Negative part.
In Sphere the Ligands are named first. In this case there are 6 CN⁻ ligands. As CN⁻ (cyanide) contains a negative charge so the -ide is replaced by -o. i.e. Cyanide → Cyano. Also, Hexa is placed before Cyano as there are 6 CN⁻ Ligands.
So,
Hexacyano
After that Chromium metal is named. As there is a negative charge on the sphere, so the -ium in Chromium is replaced by -ate.
i.e. Chromium → Chromate. And the oxidation state of Cr is written in Roman. Hence,the name is as,
Hexacyanochromate (III) Ion
<span>You take the initial minus final mass to determine how much benzene was saturated.
7.7781-5.5139 = 2.2642
Then divide by molar mass of benzene (78.11g/mol) to get the mols saturated.
2.2642/78.11 = 0.02899
Now plug into PV=nRT. After a small algebraic manipulation, we get P=nRT/V
You are given everything else. Just plug in. Don't forget to change degrees Celsius to K.
Your answer will be in atmospheres so you will need to multiply by 760 to get torr.
Your answer should be: 106.8 torr (if I plugged in correctly)</span>
7. The treatment that you vary between groups: which type of pill the patient takes
8. Plants
<span>In a chemical reaction, mass of products is same As mass of reactants.</span>
Answer:
[PCl₃] = 0.031M
[Cl₂] = 0.031M
[PCl₅] = 0.969M
Explanation:
Based on the reaction:
PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)
Keq is defined as:
<em>Keq = 1.0x10⁻³ = [PCl₃] [Cl₂] / [PCl₅]</em>
<em>Where [] are equilibrium concentrations of each species</em>
Inital [PCl₅] = 2.0mol / 2.0L = 1M.
In equilibrium:
[PCl₃] = X
[Cl₂] = X
[PCl₅] = 1M-X
Where X is reaction coordinate
Solving for X in Keq:
1.0x10⁻³ = [X] [X] / [1-X]
1.0x10⁻³ - 1.0x10⁻³X = X²
1.0x10⁻³ - 1.0x10⁻³X - X² = 0
X:
X = -0.032M. False solution, there is no negative concentration
X = 0.031M
That means equlibrium concentrations are:
[PCl₃] = 0.031M
[Cl₂] = 0.031M
[PCl₅] = 1-0.031M = 0.969M
<h3>[PCl₃] = 0.031M</h3><h3>[Cl₂] = 0.031M</h3><h3>[PCl₅] = 0.969M</h3>
