To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, that satisfy two conditions:
ac=jk and b=j+k in this case:
ac=jk=-18 and b=j+k=7 so j and k must be 9 and -2
Now replace bx with jx and kx in the original equation...
x^2-2x+9x-18 and factor the 1st and 2nd pair of terms...
x(x-2)+9(x-2) which is equal to
(x+9)(x-2)
The cross of YyRr will produce 16 distinct genotypes.
If the two alleles are far enough on the same chromosome, then the Y and R alleles will be distributed independently of one another, so that the genotypic ratio among each allele would be 1:2:1 (YY:Yy:yy, and similarly for the R allele). Then the dihybrid cross will yield a genotypic ratio of 1:2:1:2:4:2:1:2:1 (YYRR:YYRr:YYrr:YyRR:YyRr:Yyrr:yyRR:yyRr:yyrr).
Now, assuming perfect Mendelian inheritance (complete dominance), the phenotypes exhibited by YY and Yy will be considered equivalent, and similarly for RR and Rr, so the phenotypic ratio would be 9:3:3:1 (YR:Yr:yR:yr).
8.0% is the answer. To solve these problems just do actual length minus her guess which gives you 0.5. Then divide what you got by the actual length. 0.5 divided by 6.25 is 0.08. Multiply that by 100. 0.08 x 100 is 8 which means the answer is 8.0% :)
Idk if this is serious... but 10....
That equation would be right because it says solve for p. you would put p where the q is because that is the variable you need to find the answer to. and since the equation wants you to multiply you would divide when the q is switched with p so that is how you get p=q/r+s
