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const2013 [10]
3 years ago
11

Xavier starts 5 feet away from a motion detector. He then walks away from the detector at a rate of 0.5 ft/sec for 4 seconds. He

remains
still for 2 seconds, and then walks toward the detector at a rate of -2 ft/sec for 3 seconds. How far in foot is Xavier from the motion
detector when he finishes his walk?
Mathematics
1 answer:
Nitella [24]3 years ago
6 0

Answer:

1 foot

Step-by-step explanation:

5+(0.5*4)-6 = 1

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Answer:

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Step-by-step explanation:

Hello,

First of all we need to take x different from 3 as dividing by 0 is not allowed

then for x real different from 3

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Dmitriy789 [7]

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Step-by-step explanation:

Given:

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\begin{aligned}\implies (f+g)(x)=f(x)+g(x) & = (4x^2+5x-3) + (4x^3+3x^2+5) \\& = 4x^2+5x-3+4x^3+3x^2+5 \\& = 4x^3+4x^2+3x^2+5x-3+5 \\& = 4x^3+7x^2+5x+2 \\\end{aligned}

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Answer:

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