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SashulF [63]
3 years ago
13

Which of the following is an open statement?

Mathematics
1 answer:
Nana76 [90]3 years ago
3 0

Answer:

OD

Step-by-step explanation:

an angle that is more than 90 is considered a acute angles

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A fair coin is tossed three times in succession. The set of equally likely outcomes is StartSet HHH comma HHT comma HTH comma TH
liq [111]

The probability of getting exactly zero tails is 1/8.

Step-by-step explanation:

When a fair coin is tossed three time, the set of equally likely outcomes is:

S= {HHH,HHT, HTH, THH, HTT, THT, TTH, TTT}

n(S)=8

Let A be the event that there are exactly zero tails which means there are all heads

Then

A= {HHH}

n(A)=1

P(A)=\frac{n(A)}{n(S)}\\=\frac{1}{8}

The probability of getting exactly zero tails is 1/8.

Keywords: Probability, Equally likely events

Learn more about probability at:

  • brainly.com/question/13219835
  • brainly.com/question/1836777

#LearnwithBrainly

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3 years ago
The volume of a box is 8000 cubic millimeters. what is the edge length of the box?​
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If you have a picture of the problem I can answer it so just send a pic of the math problem
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3 years ago
Give the equations of 3 lines that are parallel to the line with the equation y=3x+2
ruslelena [56]
Y= 3x + 1
Y = 3x + 3
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6 0
2 years ago
A rock was thrown from the top of a cliff such that its distance above sea level was given by s(t)= at² + bt + c, where t is the
frutty [35]

Answer:

<h2>a) a = -3, b = 18, c = 48; </h2><h2>s(t) = -3t²+18t+48</h2><h2>b) 48m</h2><h2>c) 8secs</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

'A rock was thrown from the top of a cliff such that its distance above sea level was given by s(t)=at²+bt+c, where t is the time in seconds after the rock was released. After 1 second the rock was 63 m above sea level, after 2 seconds 72 m, and after 7 seconds 27 m. a. Find a, b and c and hence an expression for s(t). b. Find the height of the cliff. c. Find the time taken for the rock to reach sea level.'

Given the equation of the distance modelled as s(t)=at²+bt+c

If after 1 second the rock was 63 m, then 63 = a+b+c

If after 2 seconds, the distance was 72 m then 72 = 4a+2b+c

Also if after 7 seconds, the distance is 27 m, then 27 = 49a+7b+c

i) Solving the 3 equations simultaneously to get a, b and c we have;

a+b+c = 63 ... 1

4a+2b+c = 72 ...2

49a+7b+c = 27 ...3

Subtracting 2 from 1 and 3 from 2 we will generate 2 new equations as shown;

eqn 2- eqn1: 3a + b = 9...4

eqn 3- eqn 2: 45a + 5b = -45

eqn 3- eqn 2: 9a+b = -9 ... 5

solving 4 and 5 simultaneously

3a + b = 9 ...4

9a+b = -9 ... 5  

Taking the difference of 4 and 5 we have

6a - -9-9

6a = -18

a = -3

substituting a = -3 into equation 4 to get b we have;

3(-3)+b = 9

-9 + b = 9

b = 9+9

b = 18

substituting a = -3 and b = 18 into equation 1 to get c we have;

-3+18+c = 63

15+c = 63

c = 48

a = -3, b= 18 and c = 48

The distance function will be s(t) = -3t²+18t+48

ii) If the height of the cliff is modelled by the equation  s(t)=at²+bt+c

The height of the cliff is at when t = 0

s(0) = -3(0)²+18(0)+48

s(0) = 48m

The height of the cliff is 48m

iii) At the sea level, the height of the rock will be 0m, substituting this into the modeled equation for the height to get the time we have;

s(t)=at²+bt+c

0 = -3t²+18t+48

3t²-18t-48 = 0

t² - 6t - 16 =0

t² - 8t+2t - 16 = 0

t(t-8)+2(t-8) = 0

(t+2)(t-8) = 0

t = -2 or 8

Taking the positive value of the time, t = 8secs

Time taken for the rock to reach sea level is 8secs

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<span>It can lead to increased variance of the coefficient estimates and make the estimates very sensitive to minor changes in the model.</span>
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4 years ago
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