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dexar [7]
2 years ago
13

The box must hold 15 total soda cans. The box must hold 15 total soda cans. Sara wants to make the box as small as possible in o

rder to minimize the cost of the material used. What length, to the nearest whole centimeter, should she make the box?

Mathematics
1 answer:
harina [27]2 years ago
5 0

Answer

2

Step-by-step explanation:

It's right I had that same problem the other day and I got it correct

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Which ordered pair is a solution of the system ?
drek231 [11]
Hello!

Since we already see an equation that equals y (-2x-4), we can plug that equation into the first to solve for x.

x+4(-2x-4)=19
x-8x-16=19
-7x=35
x=-5

Now that we know the value of x, we will plug it into the second equation to solve for y.

y=-2(-5)-4
y=10=4
y=6

This gives us the answer below

\left \{ {{x=-5} \atop {y=6}} \right.

The correct answer is A) (-5,6)

I hope this helps!
7 0
2 years ago
600 x 800...................................
Mashcka [7]
First do 6×8=48, then just add the 0's to the end to get 480,000
6 0
3 years ago
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What s the Lcm of 4 and 9
Likurg_2 [28]
The LCM for 4 and 9 is 36
8 0
3 years ago
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Indicate a general rule for the n th term of this sequence. 6a, 3a, 0, -3a, -6a, . . .
GrogVix [38]
Hello : 
(-6a)-(-3a) =(-3a)-(0) = (0)-(3a) = (3a)-(6a) = -3a (arthmetic<span> sequence, the common  -  diff is : d= -3a   the first term is : U1 = 6a
</span><span>a general rule for the n th term is : Un =U1+(n-1)d
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3 0
3 years ago
In circle P with mNRQ = 60°, find the angle measure of minor arc NQ
Galina-37 [17]

Given:

m∠NRQ = 60°

To find:

The angle measure of minor arc NQ

Solution:

The inscribed angle is half of the intercepted arc.

$\Rightarrow m\angle NRQ =\frac{1}{2} m(ar NQ)

Multiply by 2 on both sides.

$\Rightarrow 2 \times m\angle NRQ =2 \times \frac{1}{2} m(ar NQ)

$\Rightarrow 2 \ m\angle NRQ =m(ar NQ)

Substitute m∠NRQ = 60°.

$\Rightarrow 2\times 60^\circ=m(ar NQ)

$\Rightarrow 120^\circ=m(ar NQ)

The measure of minor arc NQ is 120°.

8 0
3 years ago
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