The net ionic equation is written as H^+(aq) + OH^-(aq) -------> H2O(l)
<h3>What is the net ionic equation?</h3>
The term net ionic equation refers to the equation that shows the ions that underwent a change in the reaction. We have to note that the reaction species here must be ionic species which are able to dissociate into ions in solutions.
Now the first step is to put down the molecular equation. The molecular equation shows the reaction of the compounds as follows;
HCI (aq) + NaOH (ag)-> NaCI (aq) +H2O(l)
Next, we put own the complete ionic reaction equation as follows;
H^+(aq) + Cl^-(aq) + Na^+(aq) + OH^-(aq) -------> Na^+(aq) + + Cl^-(aq) + H2O(l)
Next we have the net ionic equation;
H^+(aq) + OH^-(aq) -------> H2O(l)
Learn more about ionic reaction equation:brainly.com/question/21368817
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Answer:
Hydrogen sulfide is used primarily to produce sulfuric acid and sulfur. It is also used to create a variety of inorganic sulfides used to create pesticides, leather, dyes, and pharmaceuticals. Hydrogen sulfide is used to produce heavy water for nuclear power plants (like CANDU reactors specifically).
Explanation:
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Answer:
If, for example, we want to know how many moles of oxygen will react with 17.6 mol ... Write the balanced chemical reaction for the combustion of C 5H 12
Explanation:
Answer : The percentage aniline protonated is, 0.0209 %
Explanation :
First we have to calculate the pOH.
Now we have to calculate the hydroxide ion concentration.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
![5.68=-\log [OH^-]](https://tex.z-dn.net/?f=5.68%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=2.09\times 10^{-6}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D2.09%5Ctimes%2010%5E%7B-6%7DM)
The equilibrium chemical reaction will be:
From the reaction we conclude that,
Concentration of 
ion = Concentration of 
ion = 
Now we have to calculate the percentage aniline protonated.
Thus, the percentage aniline protonated is, 0.0209 %
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