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adelina 88 [10]
2 years ago
8

LOTS OF POINT PLS HELP!!!! What is the balanced, net ionic equation for the reaction shown below? HCI (aq) + NaOH (ag)-> NaCI

(aq) +H2P(l)

Chemistry
1 answer:
Kruka [31]2 years ago
4 0

The net ionic equation is written as H^+(aq) + OH^-(aq) -------> H2O(l)

<h3>What is the net ionic equation?</h3>

The term net ionic equation refers to the equation that shows the ions that underwent a change in the reaction. We have to note that the reaction species here must be ionic species which are able to dissociate into ions in solutions.

Now the first step is to put down the molecular equation. The molecular equation shows the reaction of the compounds as follows;

HCI (aq) + NaOH (ag)-> NaCI (aq) +H2O(l)

Next, we put own the complete ionic reaction equation as follows;

H^+(aq) + Cl^-(aq) + Na^+(aq) + OH^-(aq) -------> Na^+(aq) + + Cl^-(aq) + H2O(l)

Next we have the net ionic equation;

H^+(aq) + OH^-(aq) -------> H2O(l)

Learn more about ionic reaction equation:brainly.com/question/21368817

#SPJ1

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3 0
2 years ago
A Downs cell operating at 77.0 A produces 31.0 kg of Na.(a) What volume of Cl₂(g) is produced at 1.0 atm and 540.°C?
nignag [31]

Volume of Cl₂(g) is produced at 1.0 atm and 540.°C=4.5×10^4 L

As per the evenly distributed response

2NaCl (g) ----> 2Na(l)+ Cl2(g)

Calculate the amount of Cl2 that was formed as indicated below:

Moles of Cl2 = 31.0 kg of Na x (1000* 1 * 1 / 1*23* 2)

                   = 673.9 mol

P is equal to 1.0 atm, and T is equal to 813.15 K

when converted to Kelvin by multiplying by a factor of 273.15.

Using Cl2 as an ideal gas, determine the in the following volume:

volume = nRT/P

= 673.9 * 0.0821 * 813.15/ 1

=4.5×10^4 L

As a result, the volume of Cl2 under the given circumstances =4.5×10^4 L

Learn more about Volume here:

brainly.com/question/13338592

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3 0
1 year ago
Question 5 (1 point)
Marianna [84]

Answer:

P=12.16 atm

Explanation:

Using the formula of ideal gas law:

PV = nRT

P= nRT/V

 n= number of moles

 R= Avogadro constant = 0.0821

 T= Temperature in K => ºC + 273.15 K

P= (1.50 moles)(0.0821)( 296.15 K)/ 3.00L

P= 12.15

7 0
3 years ago
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