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adelina 88 [10]
2 years ago
8

LOTS OF POINT PLS HELP!!!! What is the balanced, net ionic equation for the reaction shown below? HCI (aq) + NaOH (ag)-> NaCI

(aq) +H2P(l)

Chemistry
1 answer:
Kruka [31]2 years ago
4 0

The net ionic equation is written as H^+(aq) + OH^-(aq) -------> H2O(l)

<h3>What is the net ionic equation?</h3>

The term net ionic equation refers to the equation that shows the ions that underwent a change in the reaction. We have to note that the reaction species here must be ionic species which are able to dissociate into ions in solutions.

Now the first step is to put down the molecular equation. The molecular equation shows the reaction of the compounds as follows;

HCI (aq) + NaOH (ag)-> NaCI (aq) +H2O(l)

Next, we put own the complete ionic reaction equation as follows;

H^+(aq) + Cl^-(aq) + Na^+(aq) + OH^-(aq) -------> Na^+(aq) + + Cl^-(aq) + H2O(l)

Next we have the net ionic equation;

H^+(aq) + OH^-(aq) -------> H2O(l)

Learn more about ionic reaction equation:brainly.com/question/21368817

#SPJ1

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The acid-dissociation constant of hydrocyanic acid (hcn) at 25.0 °c is 4.9 ⋅ 10−10. what is the ph of an aqueous solution of 0.0
vodomira [7]
According to the reaction equation:

and by using ICE table:

              CN-  + H2O ↔ HCN  + OH- 

initial  0.08                        0          0

change -X                        +X          +X

Equ    (0.08-X)                    X            X

so from the equilibrium equation, we can get Ka expression

when Ka = [HCN] [OH-]/[CN-]

when Ka = Kw/Kb

               = (1 x 10^-14) / (4.9 x 10^-10)

               = 2 x 10^-5

So, by substitution:

2 x 10^-5 = X^2 / (0.08 - X)

X= 0.0013

∴ [OH] = X = 0.0013 

∴ POH = -㏒[OH]

            = -㏒0.0013

            = 2.886 

∴ PH = 14 - POH

         = 14 - 2.886 = 11.11
5 0
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Hydrogen sulfate reacts with water to produce sulfate ions and hydronium ions: hso4−+h2o⇌so42−+h3o+ identify the conjugate acid-
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     HX_{(aq)} + H_{2}O_{(aq)} --> X_{(aq)}^{-} + H_{3}O_{(aq)}^+

When an acid "reacts" with water, water acts as the base that accepts the proton (H+) from the acid. The remaining ion that is formed after the acid has donated its proton is called the conjugate base (X^-), and the conjugate acid-base pair is HX - X^-. 

Hydrogen sulfate (HSO_{4}^-) is an ion from sulfuric acid. It is still an acid in itself and can "react" with water ((H_{2}O) to form the sulfate (SO_{4}^2-) and hydronium (H_{3}O^+)ions. 

HSO_{4(aq)}^{-} + H_{2}O_{(aq)} --> SO_{4(aq)}^{2-} + H_{3}O_{(aq)}^+

Based on the previous discussion, SO_{4(aq)}^2- is identified to be the conjugate of the acid HSO_{4(aq)}^-. Thus, the conjugate acid-base pair is HSO_{4(aq)}^{-} - SO_{4(aq)}^{2-}.
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Order the steps of the experiment below according to the scientific method. 4 Paul calculated the average time to dissolve each
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Answer:

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kolezko [41]

Answer:

hello your question is incomplete the options are missing

Determine the resultant velocity for the plane when it is travelling

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ii) To the west

answer :i)  270 i

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Explanation:

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The resultant velocity for the plane when it is travelling  

let the velocity of the wind = V2

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