Answer:
Fourth degree polynomial (aka: quartic)
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Work Shown:
There isnt much work to show here because we can use the fundamental theorem of algebra. The fundamental theorem of algebra states that the number of roots is directly equal to the degree. So if we have 4 roots, then the degree is 4. This is assuming that there are no complex or imaginary roots.
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If you want to show more work, then you would effectively expand out the polynomial
(x-m)(x-n)(x-p)(x-q)
where
m = 4, n = 2, p = sqrt(2), q = -sqrt(2)
are the four roots in question
(x-m)(x-n)(x-p)(x-q)
(x-4)(x-2)(x-sqrt(2))(x-(-sqrt(2)))
(x-4)(x-2)(x-sqrt(2))(x+sqrt(2))
(x^2-6x+8)(x^2 - 2)
(x^2-2)(x^2-6x+8)
x^2(x^2-6x+8) - 2(x^2-6x+8)
x^4-6x^3+8x^2 - 2x^2 + 12x - 16
x^4 - 6x^3 + 6x^2 + 12x - 16
We end up with a 4th degree polynomial since the largest exponent is 4.
Step-by-step explanation:
you need to show us f(x)=log x graph so we can help
For end behavior, we need to consider 2 things: the highest exponent, and the coefficient of the highest exponent.
the highest exponent is 6, an even number, which means that the end behaviors will both be ∞ or -∞.
Since the coefficient is -4, a negative number, the end behaviors will both be -∞.
As x→ -∞, f(x)→ -∞. As x→ ∞, f(x)→ -∞.
U have to use Pythagoras theorem to solve this.. (adjacent)^2+(opposite)^2=hypotenuse^2
looking at the question,
the hypotenuse =15ft
opposite =12ft
adjacent =???
adjacent^2+(12)^2=15^2
a^2+144=225
group like terms
a^2=225-144
a^2=81
introduce square root to both side
root a^2=root81
a=9ft
therefore, the answer is 9ft.
