Question

Prove the identity ofs%5E%7B2%7D%20" id="TexFormula1" title=" 4 sin^{2}x + 7sin^{2} = 4 + 3cos^{2} " alt=" 4 sin^{2}x + 7sin^{2} = 4 + 3cos^{2} " align="absmiddle" class="latex-formula">
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Answer 1

Answer:

7sin

2

x+3cos

2

x=4

4sin

2

x+3sin

2

x+3cos

2

x=4

4sin

2

x+3=4

4sin

2

x=1

sin

2

x=

4

1

sinx=

2

1

or sinx=−

2

1

Step-by-step explanation:

TAKING THE POSITIVE ROOT x=

6

π

tan(

6

π

)=

3

1