The problem states that y = 12 when x = 36. 36/12 is 3. This means that y is a third of what x is. This would mean that if x = 60, y would be a third of 60 which is 20 since 60/3 is 20.
I think chocolate fairness criterion has been violated because under the unknown voting method the winner was chocolate but upon calling the store they ordered for yellow cake not chocolate
