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sp2606 [1]
2 years ago
5

A mechanic estimates that a tire still has

Mathematics
1 answer:
kati45 [8]2 years ago
6 0

Answer:

B

Step-by-step explanation:

100% is unknown 100:20 is 5

8,000*5=40,00

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Round off 86 625 mm to the nearest significant figure​
ankoles [38]

answer.

86 630

explanation.

  1. 86 62|<u>5</u>
  2. <u>8</u><u>6</u><u> </u><u>6</u><u>3</u><u>0</u>
5 0
2 years ago
2^4n × 2^ 2n = 512<br> What is the value of n.
Marina86 [1]

Step-by-step explanation:

{2}^{4n}  \times  {2}^{2n}  = 512

{2}^{4n}  \times  {2}^{2n}  =  {2}^{9}

{2}^{4n + 2n}  =  {2}^{9}

6n = 9

n  = \frac{3}{2}

8 0
2 years ago
Read 2 more answers
How do i write 3x-3y=18 in function notation
Elina [12.6K]
First you would have to isolate y.
3x - 3y = 18 -----> Subtract 3x from both sides
-3y = -3x + 18 --------> Now divide both sides by -3
y= x - 6

Now you replace the y with an f(x)
f(x) = x - 6
3 0
3 years ago
Read 2 more answers
Alexis buys groceries using her credit card her card has an APR of 19.99% and she must pay at least 5% of the balance at the end
avanturin [10]

Answer:

The answer is that she would pay $65.56 in finance charges at the end of the month.

Step-by-step explanation:

Given: APR = 19.99%

Carry Over Balance: $398.97

The APR or Annual Percentage Rate, is calculated daily. You will need to get the daily periodic rate, or DPR, so divide the APR by 365:

19.99% = .1999

.1999 / 365 = .005477 (This is the Approximate DPR, rounded up to .005477)

To get the finance charge, multiply the average daily balance by the DPR and then by 30 days:

398.97 * .005477 * 30 = $65.56 finance charge for this carry over balance, at the end of the month. This assumes that the balance is the average daily balance.

Hope this helps!!  Have a great day!

7 0
3 years ago
Identify the sequence graphed below and the average rate of change from n = 1 to n = 3.
dsp73

Answer:

The required sequence is a_n=20(\frac{1}{2})^{n-1}. The average rate of change from n = 1 to n = 3 is -7.5.

Step-by-step explanation:

From the given graph it is clear that the sequence is a GP because the all terms are half of their previous terms.

Here, a_2=10,a_3=5,a_4=2.5,a_5=1.25

r=\frac{a_3}{a_2}=\frac{5}{10}=\frac{1}{2}

The common ratio of GP is 1/2.

r=\frac{a_2}{a_1}

\frac{1}{2}=\frac{10}{a_1}

a_1=20

The first term of the sequence is 20.

The formula for sequence is

a_n=a(r)^{n-1}

Where a is first term and r is common difference.

The required sequence is

a_n=20(\frac{1}{2})^{n-1}

The formula for rate of change is

m=\frac{f(x_2)-f(x_1)}{x_2-x_1}

The average rate of change from n = 1 to n = 3 is

m=\frac{f(3)-f(1)}{3-1}

m=\frac{5-20}{3-1}

m=\frac{-15}{2}=-7.5

Therefore the required sequence is a_n=20(\frac{1}{2})^{n-1}. The average rate of change from n = 1 to n = 3 is -7.5.

8 0
3 years ago
Read 2 more answers
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