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2 years ago

A

Mathematics

1 answer:

TiliK225 [7]2 years ago

6 0

Answer:

What are you asking? If you're asking for the area of the prism, it's 774in².

Step-by-step explanation:

First you need to use this formula.

2(wl + hl + hw)

w = width

l = length

h = height

Since we already know what all of those values are, we don't need to do any solving for them.

In this case:

width = 9

length = 9

height = 17

Plug those numbers into the formula and solve.

2(9 × 9 + 17 × 9 + 17 × 9)

It would be easiest to multiply the numbers before doing your adding.

2(81 + 153 + 153)

Add.

2(387)

Multiply what is in the parenthesis with the number on the outside, 2.

There's your answer, 774.

Since this is area, you have to specify the type of measuring you're using (example: inches, feet, yards) and you have to be sure to include the ² after the measurement you're using because you may get points off for that.

774in²

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If x2 = 30, what is the value of x?

nataly862011 [7]

Subtract 30, then factor the equation.

... x² = 30

... x² - 30 = 0

... (x -√30)(x +√30) = 0

By the zero product rule, the solutions are values of x that make a factor be zero.

... x - √30 = 0 . . . . the first factor is zero

... x = √30

... x + √30 = 0 . . . . the second factor is zero

... x = -√30

The solutions are . . .

... x = ±√30 . . . . . matches your 3rd choice

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kkurt [141]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
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\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
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$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\

\end{array}\\$

$\bf \begin{array}{llll}
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\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
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\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
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$

now, notice the template above... now let's see your function $\bf y=x^2+4\implies 
\begin{array}{llllll}
y=&1(&1x&+&0)^2+&4\\
&A&B&&C&D
\end{array}$

so.. what do you think was the shift then?

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