To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
Answer:
Your slope is -1
Step-by-step explanation:
Find the change in x and the change in y and put it in change in y over change in x.
Δx = -1 - -2 = 1
Δy = -1 - 0 = -1
Slope = rise over run = Change in y over change in x = Δy/Δx = -1/1
Therefore the slope is -1/1 which is written as just -1
<h3>Given :-</h3>
<h3>To Find :-</h3>
<h3>Solution :-</h3>
☼︎ <u>Radius of the Circle</u>;
<h3>Using Formula:</h3>
<u>Putting values in the formula;</u>
henceforth, the Radius of a circle is 14 cm ...!!