*See attached picture for the diagrams being referred to
Answer:
C. ⁵/12= ²/x
Step-by-step Explanation:
Given that rectangle EFGH is similar to rectangle JKLM, it means the corresponding sides of both rectangles are similar, and as such the ratios if the corresponding sides of rectangle EFGH and rectangle JKLM would be equal.
Thus, EF/JK = FG/KL
Since, EF = 5; JK = 12; FG = 2; and KL= x, therefore, the proportion to use in finding x would be:
⁵/12= ²/x
Answer:
2 a
Step-by-step explanation:
Possible derivation:
d/dx(2 a x + 2 a y)
Differentiate the sum term by term and factor out constants:
= 2 a (d/dx(x)) + d/dx(2 a y)
The derivative of x is 1:
= d/dx(2 a y) + 1 2 a
The derivative of 2 a y is zero:
= 2 a + 0
Simplify the expression:
Answer: 2 a
Answer:
I think it is C
Step-by-step explanation:
im sorry if i am wrong
It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.
Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is
<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)
The cosine of the angle between the vectors can be obtained from the dot product identity,
<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>) ==> cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)
so that
<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)
For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is
<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))
==> <em>W</em> ≈ 5.12 J
(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).
Answer:
1.4x 2 +7x−9
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