What do I do, please help<br>or just tell me the answer

Two ways to write a algebraic expression of n-5

deff fn [24]

-5 + n is another way to write the expression.

5 0

3 years ago

Emily's vacuum cleaner has a power rating of 200 watts. If the vacuum cleaner does 360,00 joules of work, how long did Emily spe

MArishka [77]

1,800 hrs? im not sure tbh

8 0

2 years ago

a broker gets rs 20000 as commission from sale of a piece of land which costs rs 8000000. Find the rate of commission.

Airida [17]

Answer:

0.25%

Step-by-step explanation:

Rate of commission

= (commission*100)/cost of land

=( 20000*100)/8000000

= 2000000/8000000

=2/8

= 0.25%

3 0

2 years ago

a store owner wishes to make a new tea with a unique flavor by mixing black tea and oolong tea. if he has 35 pounds of oolong te

Verizon [17]

35 pounds of black tea is needed to be mixed to get the final mixture for 2.10 per pound

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the amount of black tea worth 1.80 per pound to be mixed to get the final mixture for 2.10 per pound, hence:

2.4(35) + 1.8(x) = 2.1(x + 35)

x = 35 pounds

35 pounds of black tea is needed to be mixed to get the final mixture for 2.10 per pound

Find out more on equation at: brainly.com/question/2972832

#SPJ1

3 0

1 year ago

A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a

netineya [11]

Answer:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(X \geq 5)$

And we can use the complement rule: