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yaroslaw [1]
2 years ago
10

Hello please help i’ll give brainliest

Mathematics
2 answers:
Dennis_Churaev [7]2 years ago
8 0
Maximum is 20 but the guy is right about everything else
bearhunter [10]2 years ago
3 0

Answer:

Minimum = 10

Q1 (quartile 1) = 14.5

Medium = 16

Q3 (quartile 3) = 17

Maximum = 18

Step-by-step explanation:

You just arrange the numbers in from smallest to greatest (even if some of them repeat). Then, look for the maximum and minimum. Get the median by having the same numbers left from both sides until reaching the median. The same holds for the quartiles (if you have for example two numbers for the quartile, as in this case 14 and 15, add the up and divide them by 2, in this case 14.5.

Tell me if I'm correct please  

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Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

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\sqrt{n} = \frac{1.2996}{0.07}

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(\sqrt{n})^{2} = (18.5658)^{2}

n = 345

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
3 years ago
HELP ME ASAP!!! PLEASE FAST!
ryzh [129]
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3 years ago
25% of 80 = what percent???
Doss [256]

First off, you really don't need to write "what percent???" here.  

25% of 80 is 0.25(80) = 20.  

4 0
3 years ago
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