Answer:
10.
x P(X)
0 0.238
1 0.438
2 0.269
3 0.055
11.
0.707
There is 70.7% chance that at least one but at most two adults in the sample believes in the ghost
12.
1.14≅1
There will be one adult out of three we expect to believe in the ghost
Step-by-step explanation:
The probability distribution is constructed using binomial distribution.
We have to construct the probability distribution of the number adults believe in ghosts out of three adults. so,
x=0,1,2,3
n=3
p=probability of adults believe in ghosts=0.38
The binomial distribution formula
nCxp^xq^n-x=3cx0.38^x0.62^3-x
is computed for x=0,1,2,3 and the results depicts the probability distribution of the number adults believe in ghosts out of three adults.
x P(X)
0 0.238
1 0.438
2 0.269
3 0.055
11.
P(at least one but at most two adults in the sample believes in the ghost )= P(x=1)+P(x=2)=0.437+0.269=0.707
P(at least one but at most two adults in the sample believes in the ghost )=70.7%
12. E(x)=n*p
here n=3 adults and p=0.38
E(x)=3*0.38=1.14
so we expect one adult out of three will believe in the ghosts.
What’s the subject?
20 characters really???
A little playing around with plane figures (and/or distance equations) will convince you that this set of points is a sphere centered at
... c = (4b -a)/3 = (25/3, 1, -11/3) . . . . center
with a radius 2/3 of the length ab.
... r = (2/3)√(7² +3² +5²) = (2/3)√83 . . . . radius
Then the equation of this spherical set of points is
... (x -25/3)² +(y -1)² +(z +11/3)² = 332/9