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3 years ago

Help please Which number sentence below matches this word problem?

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

4 0

Answer:

I think it's d

Step-by-step explanation:

Nit 100% sure but if nit its b

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Find the product. Simplify if possible.

tankabanditka [31]

Answer:

B) 2/11

Step-by-step explanation:

(4/2a)(a/11)

4/2a=2/a

(2/a)(a/11)=2/11

5 0

4 years ago

Pls help for math homework. Show work.

vichka [17]

12x - 13 - x - 9 + 10x

First, get the like terms together

12x + 10x - x -13 -9

Now, combine like terms

12x + 10x - x = 21x

-13 - 9 = -22

Final Answer:

21x - 22

5 0

3 years ago

Given AG bisects CD, IJ bisects CE, and BH bisects ED. Prove KE = FD.

OverLord2011 [107]

When a line is bisected, the line is divided into equal halves.

See below for the proof of $\mathbf{KE \cong FD}$

The given parameters are:

AC bisects CD
IJ bisects CE
BH bisects ED

By definition of segment bisection, we have:

$\mathbf{CK \cong KE}$
$\mathbf{EF \cong FD}$
$\mathbf{CE \cong ED}$

By definition of congruent segments, the above congruence equations become:

$\mathbf{CK = KE}$
$\mathbf{EF = FD}$
$\mathbf{CE = ED}$

By segment addition postulate, we have:

$\mathbf{CE = CK + KE}$
$\mathbf{ED = EF + FD}$

Substitute $\mathbf{ED = EF + FD}$ in $\mathbf{CE = ED}$

$\mathbf{CK + KE = EF + FD}$

Substitute $\mathbf{CK = KE}$ and $\mathbf{EF = FD}$

$\mathbf{KE + KE = FD + FD}$

Simplify

$\mathbf{2KE = 2FD}$

Apply division property of equality

$\mathbf{KE = FD}$

By definition of congruent segments

$\mathbf{KE \cong FD}$

Read more about proofs of congruent segments at:

brainly.com/question/11494126

6 0

3 years ago

I need Urgent help on this please !!

Feliz [49]

Answer:

6 2 6 2 6 6 1

Step-by-step explanation:

8 0

3 years ago

*GEOMETRY!!!!*

goldenfox [79]

Answer:

im in 7th grade

Step-by-step explanation:

7 0

3 years ago