Question

Two pure-breeding lines of orange trees differ in the number of fruit segments they contain: One line produces fruit with 6 segments, and the other produces fruit with 10 segments. When these lines are crossed, the F1 produces fruit with 8 segments. When the F1 trees are crossed, the resulting F2 has nine phenotypic classes of trees, producing fruit with as few as 4 segments and as many as 12Assume that fruit segment number in orange trees is determined entirely by multiple unlinked, additive alleles.
Using the information above, complete the following statements by dragging one blue label to each blue target and one pink label to each pink target. Blue labels may be used once, more than once, or not at all.

Answer 1

Answer:

from the image:

1. eight

2. four

3. less than

Explanation:

from the data given...

n= 4

where n= # of genes

&, the extreme # of segments=   $(\frac{1}{4} )^{n}$

Genes, which make up a genotype are instructions for encoding a phenotype, expressed as proteins in translation.

...one gene may have 2 alleles

An allele is an alternate form of a particular gene. Genes can have multiple alleles, but in this case...

∴4 genes= 4 × 2= 8 segments

Thus, each allele gives $\frac{8}{8}$ = 1 segment