There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
97 would be the answer 5 x 5 = 25 5 x 3 = 15 25-15= 10+87= 97
Area = length x width
area = 2 3/4 x 2/5
area = 1 1/10 feet :)
The answer for the question is 36 , 36
Answer:
14,334 actually that might not be the answer im just thinking that because the 4 is in the tenths place and ur rounding that u would make it into a whole number
