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lorasvet [3.4K]
3 years ago
14

align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
sergey [27]3 years ago
8 0
This is about 2.2 in decimal form. I don’t know what you are supposed to do.
Schach [20]3 years ago
7 0

Answer:

три три быдет три незнаю точно

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Stacey filled her 1/2 cup measuring cup seven times to have enough flour does the cake récipe. How much flour does the cake reci
yan [13]
All we need to do to find the answer is to multiply 1/2 by 7:

1/2 * 7 =
= 7/2 =
= 3 1/2

Answer: The cake recpipe calls for 3 1/2 cups of flour.

I hope it will help you ;)
5 0
4 years ago
What is the range of the function on the graph?
Marta_Voda [28]

Answer:

no. 4

Step-by-step explanation:

the numbers start at two and keeps going up.

3 0
3 years ago
Read 2 more answers
Based on the theoretical probability, how many times would you expect to pick a yellow skittle if you pick 150 times?
Fudgin [204]

Answer:

why are you digging through skittles 150 times?

8 0
3 years ago
Read 2 more answers
Find the values of the variables for which ABCD must be a parallelogram
sleet_krkn [62]

Answer:

y=5 and x=4

Step-by-step explanation:

So,the diagonals of a parallelogram bisect each other..

therefore,we have our two eqn

4x-2=3y-1------------(i)

3y-3=3x

or,y-1=x----------(ii)

Now,simply substitute value of x in eqn (i)

4(y-1)-2=3y-1

or,4y-4-2=3y-1

or,y=5

Again,substitute y=5 in eqn (ii)

5-1=x

therefore,

x=5

Hope it helps you!!!

4 0
4 years ago
Write a linear function f with the values f(-4) = 0 and f(0) =0 please help
Sergeeva-Olga [200]

f(\stackrel{x_1}{-4})=\stackrel{y_1}{0}\qquad f(\stackrel{x_2}{0})=\stackrel{y_2}{0}~\hfill (\stackrel{x_1}{-4}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{0}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{0}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-4)}}}\implies \cfrac{0}{0+4}\implies \cfrac{0}{4}\implies 0

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{0}(x-\stackrel{x_1}{(-4)})\implies \boxed{y = 0}

6 0
3 years ago
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