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erastova [34]
3 years ago
11

How many atoms are in 5 moles of Cadmium?

Chemistry
1 answer:
forsale [732]3 years ago
5 0
<h3>Answer:</h3>

3 × 10²⁴ atoms Cd

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

5 mol Cd (Cadmium)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 5 \ moles \ Cd(\frac{6.022 \cdot 10^{23} \ atoms \ Cd}{1 \ mol \ Cd})
  2. Multiply:                              \displaystyle 3.011 \cdot 10^{24} \ atoms \ Cd

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

3.011 × 10²⁴ atoms Cd ≈ 3 × 10²⁴ atoms Cd

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Consider the following chemical equilibrium: 4NH3+3O2=2N2+6H2O Now write an equation below that shows how to calculate from for
erma4kov [3.2K]

This is an incomplete question, here is a complete question.

Consider the following chemical equilibrium:

4NH_3(g)+3O_2(g)\rightleftharpoons 2N_2(g)+6H_2O(g)

Now write an equation below that shows how to calculate Kp from Kc for this reaction at an absolute temperature T. You can assume T is comfortably above room temperature. If you include any common physical constants in your equation be sure you use their standard symbols, found in the ALEKS Calculator.

Answer :

The expression of K_c will be,

K_c=\frac{[N_2]^2[H_2O]^6}{[NH_3]^4[O_2]^3}

The expression of K_p will be,

K_p=K_c(RT)

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

4NH_3(g)+3O_2(g)\rightleftharpoons 2N_2(g)+6H_2O(g)

The expression of K_c will be,

K_c=\frac{[N_2]^2[H_2O]^6}{[NH_3]^4[O_2]^3}

The relation between K_p and K_c is:

K_p=K_c(RT)^{\Delta n}

Form the above reaction we conclude that:

\Delta n=n_{product}-n_{reactant}

\Delta n=(6+2)-(4+3)

\Delta n=1

The expression of K_p will be,

K_p=K_c(RT)^{1}

K_p=K_c(RT)

7 0
3 years ago
What current (in a) is required to plate out 2. 96 g of nickel from a solution of ni2 in 27. 12 minutes?
amid [387]

The current required to plate out 2.96 g of nickel from the solution of Ni²⁺ in 27.12 minutes is 5.95 A

<h3>Balanced equation </h3>

We'll begin by writing the balanced equation showing the number of faraday required to plate nickel. This is given below

Ni²⁺ + 2e —> Ni

Molar mass of Ni = 59 g/mol

Mass of Ni from the balanced equation = 1 × 59 = 59 g

Number of faraday = 2 F

1 faraday = 96500 C

2 faraday = 2 × 96500 = 193000 C

SUMMARY

From the balanced equation above,

59 g of Nickel was deposited by 193000 C of electricity

<h3>How to determine the quantity of electricity </h3>

From the balanced equation above,

59 g of Nickel was deposited by 193000 C of electricity

Therefore,

2.96 g of Nickel will be deposited by = (2.96 × 193000) / 59 = 9682.71 C of electricity

<h3>How to determine the current </h3>
  • Quantity of electricity (Q) = 9682.71 C
  • Time (t) = 27.12 mins = 27.12 × 60 = 1627.2 s
  • Current (I) =?

I = Q / t

I = 9682.71 / 1627.2

I = 5.95 A

Learn more about Faraday's law:

brainly.com/question/24795850

6 0
2 years ago
Read 2 more answers
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Ede4ka [16]
Calculus, originally called infinitesimal calculus or "the calculus of infinitesimals", is the mathematical study of continuous change, in the same way that geometry is the study of shape and algebra is the study of generalizations of arithmetic operations.
3 0
3 years ago
What is the mass of sodium (Na) in 50 grams of table salt (NaCl)? Show your work.
beks73 [17]

Answer:

The amount of sodium in this sample = 32.4 grams

Explanation:

Mass of Sodium = 23 g/mol

Mass of Chlorine = 35.5 g/mol

Mass of NaCl = 35.5 g/mol

Fraction of Na in NaCl = \frac{23}{35.5}

                                      =0.648

We are given a sample of 50 grams of sodium chloride.

The amount of sodium in this sample = Amount of sodium in 1 gram sample \times weight of sample

The amount of sodium in this sample = 0.648 \times 50

The amount of sodium in this sample = 32.4 grams

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You have exactly 1.722 x 10^3 eggs. Calculate the dozens of eggs that you have.
Marina CMI [18]

1.722 \times  {10}^{3}  = 1722\: eggs

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