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uranmaximum [27]
3 years ago
9

A car driving east along the freeway at 60 m/s hits some traffic and after 7 seconds is

Chemistry
1 answer:
Vladimir79 [104]3 years ago
4 0
Do u know how to solve area
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Draw the addition product formed when one equivalent of hcl reacts with the following diene.
pashok25 [27]

Answer:

                    Major Product = 4-chloro-4-methylcyclohex-1-ene

Explanation:

                     Alkene are the class of organic compounds which contain one or more double bonds between two carbon atoms. Alkenes are considered most reactive among the unsaturated hydrocarbons and they undergo <em>addition reactions</em> due to high electron density around the double bonds.

                      In given question it is written that we are provided with one equivalent of HCl while, our compound contains two double bonds (diene) so in selected starting material the HCl will be added across (hydrohalogenation reaction) the substituted double bond because it will give a more stable carbocation (<u><em>tertiary carbocation</em></u>) during the reaction course. Hence, as shown in reaction scheme 4-chloro-4-methylcyclohex-1-ene will be the major product.

5 0
2 years ago
Would you expect manganese(II) oxide, MnO, to react more readily with HF(aq) or NaOH(aq)?
ella [17]

Answer:

NaOH(aq)

Explanation:

NaOH(aq) is known to precipitate Mn^2+ ions according to the following reaction; Mn^2+(aq)+2OH^−(aq)↽−−⇀Mn(OH)2(s)

Hence, manganese(II) oxide reacts more readily with NaOH(aq) under ordinary conditions precipitating the metal hydroxide solid. This is one of the characteristic reactions of Mn^2+.

3 0
3 years ago
convert 0.876 atm to mmHg. solution: multiply the atm value by 760.0 mmHg/ 1.0 atm 0875 atm x _______ = _______ mm Hg (3 sig fig
Akimi4 [234]

\tt \dfrac{760~mmHg}{1~atm}\times 0.876~atm=665~mmHg

5 0
1 year ago
***URGENT PLEASE**** Select all of the bases listed *
Masteriza [31]

Answer:

NaOH (a strong base)

Ammonia ( weak base )

6 0
2 years ago
Balance the equation
andrezito [222]
Balanced equation: shown in photo

6 0
2 years ago
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