Question

According to the molecular orbital energy-level diagram below, which one of the following statements is not correct about NO, NO+, and NO−? These molecular orbitals are formed from the 2s and 2p atomic orbitals.

Answer 1

None of the statement is not correct about NO, NO+, and NO−.

Explanation:

Those molecules whose all subshells are completely filled are diamagnetic.

Those molecules whose any sub-shell is incomplete is termed paramagnetic.

Let us check the magnetism in all three molecules based on molecular orbital theory and Lewis structure

NO= number of electrons 11

It form N=O having configuration 1s2,2s2,2p6,3s1, it has 1 unpaired electron so it is paramagnetic.

Now NO-, number of electrons 12 having configuration 1s2,2s2,2p6,3s2, no unpaired electron hence dimagnetic.

Now NO+, number of electrons is 10 having configuration 1s2,2s2,2p6,3s2, dimagnetic

Let us calculate the bond order of NO-

N0- have 12 electrons as 5 of nitrogen, 6 of oxygen and 1 of - charge on oxygen.

So, bond order = $\frac{8-4}{2}$

                          = 2 double bonds

bond order of NO+, Number of electrons is 10

bond order= $\frac{8-2}{2}$

bond order = 3

bond order of NO, number of electrons 11

bond order= $\frac{8-3}{2}$

bond order=2.5

Larger the bond order shorter the bond.