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3 years ago

11

Solve the equation graphically in the given interval. State each answer rounded to two decimals. (Enter your answers as a comma-

separated list.)
16x3 + 16x2 = x + 1; [−2, 2]

1 answer:

andreyandreev [35.5K]3 years ago

5 0

Answer:

kjmalopiuajkm;l'aojsdnkjdfla

Step-by-step explanation:

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3 years ago

HELP!!<br>Find the third term of (x^2+3y)^3

lana66690 [7]

Answer:

$T_{3}=27{x}^{2}y^2$

Step-by-step explanation:

The given binomial expression is:

$( {x}^{2} + 3y)^{3}$

When we compare to:

${(a +b)}^{n}$

We have

$a = {x}^{2}$

$b = 3y \\ n = 3$

The nth term is given by;

$T_{r+1}=^nC_ra^{n-r}b^r$

To find the 3rd term, we put:

$r + 1 = 3 \\ r = 2$

We substitute into the formula to get:

$T_{3}=^3C_2( {x}^{2} )^{3-2}(3y)^2$

We simply:

$T_{3}=3( {x}^{2} )^{1} \times 9y^2$

$T_{3}=27{x}^{2}y^2$

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3 years ago