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joja [24]
4 years ago
13

Question 1: Car A began a journey from a point at 9 am, traveling at 30 mph. At 10 am car B started traveling from the same poin

t at 40 mph in the same direction as car A. At what time will car B pass car A?
Mathematics
2 answers:
-BARSIC- [3]4 years ago
6 0
Let after t hours the distances D1 traveled by car A

 D1 = 30 t

Car B starts at 10 am and will therefore have spent one hour less than car A when it passes it.

After (t - 1) hours, distance D2 traveled by car B

 D2 = 40 (t - 1)

When car B passes car A, they are at the same distance from the starting point and therefore<span> D1 = D2 </span>

 30 t = 40 (t - 1)

Solve the equation for t,

 30 t = 40t - 40

 10 t = 40

 t = 4

<span> Car B passes car A at = 9 + 4 = 1 pm.</span>
Leya [2.2K]4 years ago
3 0
The answer is 1 pm I know because I did the equation on paper it took me a minute
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