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SashulF [63]
3 years ago
14

Solve for x:5/7 = 4x/83​

Mathematics
1 answer:
Simora [160]3 years ago
7 0

Step-by-step explanation:

\to  \dfrac{5}{7}  =  \dfrac{4x}{83}

By cross multiplication,

→ 83(5) = 4x(7)

→ 415 = 28x

<h3>→ 415/28 = x</h3>

  • In decimal : 14.8214286

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the answer is k=4.6. hope this helps

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3 years ago
The probabilty that a student owns a car is 0.65 the porbability that a student owns a compuer is 0.82 the probability that a st
DanielleElmas [232]

Question:  The probability that s student owns a car is 0.65, and the probability that a student owns a computer is 0.82.

a. If the probability that a student owns both is 0.55, what is the probability that a randomly selected student owns a car or computer?

b. What is the probability that a randomly selected student does not own a car or computer?

Answer:

(a) 0.92

(b) 0.08

Step-by-step explanation:

(a)

Applying

Pr(A or B) = Pr(A) + Pr(B) – Pr(A and B)................. Equation 1

Where A represent Car, B represent Computer.

From the question,

Pr(A) = 0.65, Pr(B) = 0.82, Pr(A and B) = 0.55

Substitute these values into equation 1

Pr(A or B) = 0.65+0.82-0.55

Pr(A or B) = 1.47-0.55

Pr(A or B) = 0.92.

Hence the probability that a student selected randomly owns a house or a car is 0.92

(b)

Applying

Pr(A or B) = 1 – Pr(not-A and not-B)

Pr(not-A and not-B) = 1-Pr(A or B) ..................... Equation 2

Given: Pr(A or B)  = 0.92

Substitute these value into equation 2

Pr(not-A and not-B) = 1-0.92

Pr(not-A and not-B) = 0.08

Hence the probability that a student selected randomly does not own a car or a computer is 0.08

8 0
2 years ago
I need help with 27 and 28 show step and round to nearest tenth
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Answer:

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Step-by-step explanation:

Hope this helped! Please rate it if this helped!

5 0
3 years ago
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but diagonal (z) = sqrt(2x^2)
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Thus, A = 1/2 z^2
dA/dz = 1/2 (2z) = z
The rate of change is z.

When z = 4, the rate is 4.
4 0
3 years ago
What is the lateral area of the rectangular prism with a base length of 17 m, a base width of 7 m, and a height of 5 m?
mrs_skeptik [129]
length: \ l=17 \ m \\width = \ 7 \ m\\ height:\ 5 \ m \\\\ lateral \ area \ =(2l+2w)\cdot h \\ \\A_{l} = (2\cdot 17+2\cdot 7)\cdot 5=(34+14)\cdot 5=48\cdot 5=240 \ m^2


4 0
3 years ago
Read 2 more answers
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