Terrell is moving boxes in a freight elevator. Each box weighs about 25 pounds. For safety reasons, a maximum of 600 pounds can
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
The sample space of rolling a dice twice is:
S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
Sample size, <em>n</em> = 36.
Each sample has an equal chance of being selected.
So the probability of selecting any of the 36 sample is, .
Now an event <em>A</em> is defined as the second roll being larger than the first.
The sample space for <em>A</em> is:
<em>A</em> = {(2, 1), (3, 1), (3, 2), (4, 1), (4, 2), (4, 3), (5, 1), (5, 2), (5, 3), (5, 4), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5)}
The sample size is, <em>n</em> = 15.
The probability of the event <em>A</em> is:
Answer:
standard divisor: 525.00
Step-by-step explanation:
The standard divisor is found by dividing the total number of residents to be represented, by the number of representatives. Here, that is 7875 divided by 15. The resulting standard divisor is 525 (exactly).
By Hamilton's method, the number of residents in each district is divided by this number, and the integer and fraction of the quotient are recorded.
If the total of integers is less than the total number of representatives, then the difference is apportioned to the districts according to the values of the fractions.
Here, the total of quotient integers is 13, so 2 additional representatives need to be apportioned. The two largest fractions are 0.77 associated with District 5, and 0.58 associated with District 1. These two districts, then, get the "extra" representatives. (1 is added to the "integer" for those districts.)
Final assignments of representatives to districts are seen in the rightmost column of the spreadsheet.
