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3 years ago

The angles opposite the congruent sides of an isosceles triangle are congruent find the value of x in the triangle

2 answers:

7 0

Base angle + base angle + 70degrees = x degrees
x + x + 70 degrees = x degrees
2x + 70 = x
2x = 70 - x
2x = 60
x = 70.2
<span>x = 35</span>

nalin [4]3 years ago

6 0

The answer is <em>70!!!</em>

<em>I took the test on edgenuity </em>

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A wholesaler requires a minimum of 4 items in each order from its retail customers. The manager of one retail store is consideri

Leto [7]

Answer:

The 1st graph will be perfectly matching the conditions.

Step-by-step explanation:

A wholesaler requires a minimum of 4 items in each order from its retail customers.

The manager of one retail store is considering ordering a certain number of sofas, x and a certain number of pillows that come in pairs, y.

Therefore, for y = 0, x ≥ 4 and for x = 0, y ≥ 2 to make the order of 4 items or more.

Therefore, the equation for the order to be of 4 items will be

x + 2y = 4.

So, the 1st graph will be perfectly matching the conditions. (Answer)

3 0

2 years ago

Cody stamped 460 envelopes in 30 minutes. How many envelopes per minute did Cody stamp?

Leokris [45]

Answer:

15 1/3 envelopes in 1 minutes

Step-by-step explanation:

Take the number of envelopes and divide by the number of minutes

460 envelopes / 30 minutes

15.333333.... envelopes per minute

15 1/3 envelopes in 1 minutes

3 0

2 years ago

See question in attached photo.<br>Answer question 4b and 5c

sdas [7]

9514 1404 393

Answer:

4b: 8.6 m/s²; 1.3×10^5 N; 2.1×10^4 N decrease

5c: -1.6×10^12 J; -1.6×10^12 J

Step-by-step explanation:

i) The acceleration due to gravity is inversely proportional to the square of the distance between the objects. The distance to the shuttle is ...

1 + (5×10^5)/(6.4×10^5) = 69/64 . . . times the radius of the earth

Then the acceleration due to gravity at the height of the space shuttle is about ...

(10 m/s²)(64/69)² ≈ 8.6 m/s²

ii) The weight of the space shuttle at that height is about ...

F = ma = (15000 kg)(8.6 m/s²) ≈ 1.3×10^5 N

iii) The loss of weight will be ...

ΔF = m(a1 -a0) = (15000 kg)(10 m/s² -8.6 m/s²)

= 1.5×10^4×1.4 N = 2.1×10^4 N

____

i) The gravitational potential energy is given by ...

U = -GMm/r

where M and m are the mass of the earth and the rocket, respectively.

U = -(6.67×10^-11)(6.0×10^24)(2.5×10^4)/(6.4×10^6) ≈ -1.6×10^12 J

ii) At a height of 3×10^4 m, the denominator in the above expression changes from 6.4×10^6 to 6.43×10^6. This changes the gravitational potential energy by a factor of 6.4/6.43 to -1.6×10^12 J

(Note: we're carrying only 2 significant figures in the result in accordance with the rules for precision in such calculations. The change is noticeable at the level of the 4th significant figure, less than 1/2%.)

4 0

2 years ago

Charlie guesses that his dog weighs 34. 5 pounds. The dog actually weighs 32. 7 pounds. What is the percent error in Charlie’s g

expeople1 [14]

Percent error is the amount of error to actual value, in percent. The percent error in Charlie’s guess is approximately: Option D: 5.5%

<h3>How to calculate the percent error?</h3>

Suppose the actual value and the estimated values after the measurement are obtained. Then we have:

Error = Actual value - Estimated value

To calculate percent error, we will measure how much percent of actual value, the error is, in the estimated value.

$\rm Percent \: Error = |\dfrac{Error}{Actual value}|\times 100 \\\\Percent \: Error = | \dfrac{\text{(Actual Value - Estimated Value)}}{Actual value}|\times 100 \\$

(here |x| is such that it makes x non negative, thus, |-5| = 5, and |5| = 5)

For the given case, it is specified that:

Actual weight of dog = 32.7 pounds

Guessed weight of dog, by Charlie : 34.5 pounds.

Error = 32.7 - 34.5 = -1.8 pounds

Thus, percent error in Charlie's guess is calculated as:

$\text{Percent Error} = |\dfrac{-1.8}{32.7}| \times 100 \approx 5.5\%$

Hence, the percent error in Charlie’s guess is obtained approximately is given by: Option D: 5.5%

Learn more about percent error here:

brainly.com/question/25749180

3 0

2 years ago

50 POINTS!!!!

Softa [21]

Answer:

Step-by-step explanation:

Given that X - the distribution of heights of male pilots is approximately normal, with a mean of 72.6 inches and a standard deviation of 2.7 inches.

Height of male pilot = 74.2 inches

We have to find the percentile

X = 74.2

Corresponding Z score = 74.2-72.6 = 1.6

P(X<174.2) = P(Z<1.6) = 0.5-0.4452=0.0548=5.48%

i.e. only 5% are below him in height.

Thus the malepilot is in 5th percentile.

3 0

1 year ago